The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that could result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female). a. Possible genotypes for Black coat: Chestnut coat: b. Possible genotypes for Trotting gait: Pacing gait: . c. Male genotype_ gametes possible gametes_ Male possible d. Female genotype_ Female e. Gametes
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The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that could result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female).
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- In a trihybrid cross involving three traits where the parents are AaBbCc. (a) What is the probability of them producing an offspring recessive for all three traits? (b) What is the probability of offspring with phenotype A_bbc_?In a dihybrid cross of two bi-allelic Mendelian genes, A (two alleles – completely dominant A and recessive a), and B (two alleles – completely dominant B and recessive b), such that the parental generation comprises of pure-bred homozygotes (i.e. AABB with aabb), what are the expected genotype and phenotype ratios in the F1 and F2, if the F1 cross is (a) an intercross and if the F1 cross is (b) a testcrossIn the shorthorn breed of cattle, The red and white coat colors are codominant with each other with the resulting hit rosagas condition being roan. A breeder has some white, some Roan, and some red cattle (female) And only one round bull (male).  A. What color cow would be bread to the ro bowl to guarantee the best chance of having white offspring? B. What is the probability of a red cow cross with the Roan bull resulting in a white half? explain by using parent and possible offspring genotypes.  C. What is one possible way that the farmer can guarantee having over red offspring by going outside of his breeding stock? Explain by using parent and possible offspring genotypes. 
- In the fictitious monster Lochnessius coolnameii, coat color is under the control of an autosomal gene, with white coat (W) dominant over black coat (w). The monster’s ability to produce horns is a sex-influenced trait, that is dominant in males but recessive in females. Let Horned = H, and hornless = h. Consider the cross of a homozygous white & horned male with a homozygous black & hornless female. What genotypes and phenotypes are expected in the F1? What genotypes and phenotypes are expected in the F2? In what ratios? Zappy is a horned white male. It was bred to the following four females, and the results are presented here: Mother Offspring Alcremie: hornless, black 1 horned white female Blissey: hornless, white 1 hornless black female Chansey: horned, black 1 horned, white female Delcattie: hornless, white 1 hornless, black male + 1 Horned white…In a species of tropical fish, a colorful orange andblack variety called montezuma occurs. When twomontezumas are crossed, 2/3 of the progeny are montezuma and 1/3 are the wild-type, dark grayish greencolor. Montezuma is a single-gene trait, and montezuma fish are never true-breeding.a. Explain the inheritance pattern seen here and showhow your explanation accounts for the phenotypicratios given.b. In this same species, the morphology of the dorsalfin is altered from normal to ruffled by homozygosity for a recessive allele designated f. What progenywould you expect to obtain, and in what proportions, from the cross of a montezuma fish homozygous for normal fins to a green, ruffled fish?c. What phenotypic ratios of progeny would be expected from the crossing of two of the montezumaprogeny from part (b)?The pedigree shown below illustrates the inheritance pattern for a trait controlled by a single fully penetrant gene with complete dominance. Based on the pedigree do the following: a - List one mode of inheritance consistent with the pedigree . b. using the mode listed (a) the genotypes of individuals I.2, II.5, and III.3. (if two genotypes are possible for any of these individuals, list both). asap please.
- When many families were tested for the ability to tastethe chemical phenylthiocarbamide, the matings weregrouped into three types and the progeny were totaled,with the results shown below:ChildrenNumber NonParents of families Tasters tastersTaster × taster 425 929 130Taster × nontaster 289 483 278Nontaster × nontaster 86 5 218With the assumption that PTC tasting is dominant (P)and nontasting is recessive (p), how can the progenyratios in each of the three types of mating be accountedfor?In guinea pigs, short hair is dominant to long hair. Also in guinea pigs, black eyes aredominant to red eyes. A male guinea pig that is heterozygous for both traits is crossedwith a female that is long haired and red eyed. What are the expected phenotypes oftheir offspring? Provide the phenotypic ratio as well.Assume that in horses, black coat colour is dominant (B) to chestnut colour (b). The troting gait is due to a dominat allele (T), and the pacing gait is a recessive allele (t) a) If two Black trotting horses are mated and have for offsprings, all of which are black and pacing, what does that reveal about the probable genotype of the parent horses? b)A stud is black and trotting. He is mated with a mayor who is also black and trotting. Their colt is black and pacing. The same stud is mated to a second mare who is Chestnut and pacing. Their colt is Chestnut and trotting. What is the probable genotype(s) of the stud, mare 1, colt 1, and colt 2
- In poultry, the genotype–phenotype relationships forcomb shape are R/– P/–, walnut; R/– p/p, rose, r/r P/–, pea;and r/r p/p, single. What will be the comb characters ofthe offspring of the following crosses? a. A walnut crossed with a single b. A rose crossed with a walnut c. A rose crossed with a pea d. A walnut crossed with a walnutIn rabbits, black hair is due to a dominant allele B and brown hair to its recessive allele b. Short hair (H) is dominant to long hair (h). Show punnet squares In a cross between a homozygous black, longhaired rabbit and a brown, homozygous shorthaired one, what would the F1 generation look like? If you did not know the genotype of an F1 rabbit, you could determine its genotype by a test cross in which it is crossed with an animal with which phenotype AND genotype? If you carried out this test cross (from 2, using the F1 from 1), what phenotypes and in what ratio would you expect? What phenotypes in what ratio would be expected in the F2 generation of the cross in point 1?Write the number of different kinds of phenotypes,excluding sex, you would see among a large numberof progeny from an F1 mating between individuals ofidentical genotype that are heterozygous for one ortwo genes (that is, Aa or Aa Bb) as indicated. No geneinteractions means that the phenotype determined byone gene is not influenced by the genotype of theother gene.a. One gene; A completely dominant to a.b. One gene; A and a codominant.c. One gene; A incompletely dominant to a.d. Two unlinked genes; no gene interactions; Acompletely dominant to a, and B completelydominant to b.e. Two genes, 10 m.u. apart; no gene interactions; Acompletely dominant to a, and B completely dominant to b.f. Two unlinked genes; no gene interactions; A anda codominant, and B incompletely dominant to b.g. Two genes, 10 m.u. apart; A completely dominantto a, and B completely dominant to b; and withrecessive epistasis between aa and the alleles ofgene B.h. Two unlinked duplicated genes (that is, A and Bperform…