The circuit diagram below shows a Buck converter. is de S O SV (1-8) V_ =0 de 0 O 8(V-V)-SV =0 VA O 8V (1-8) V = 0 D L The voltage and currents in the circuit can be separated into an average quantity and a ripple quantity such that x (1) =X+Ax (1), where x (1) is the signal, X is the average and Ax (1) is the ripple function. If the circuit is operated in continuous current mode with a duty ratio ō, the volt-seconds balance equation for L is given by: O 8(V-V)-(1-8) V = 0 VL ic CRV

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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The circuit diagram below shows a Buck converter.
Vdc
iL L
VL
#D
D
O 8 (V
dc
is S
Ť
The voltage and currents in the circuit can be separated into an average quantity and a ripple quantity such that x (t)=X+Ax (t), where x (t) is the signal, X is the average and Ax (1) is the ripple function.
If the circuit is operated in continuous current mode with a duty ratio 6, the volt-seconds balance equation for L is given by:
V)-(1-8) V =0
-
dc
OSV (1-8) V = 0
0
O 8(V-V)-SV = 0
dc
ic
O SV - (1-8) V = 0
1₂
C RL V
Transcribed Image Text:The circuit diagram below shows a Buck converter. Vdc iL L VL #D D O 8 (V dc is S Ť The voltage and currents in the circuit can be separated into an average quantity and a ripple quantity such that x (t)=X+Ax (t), where x (t) is the signal, X is the average and Ax (1) is the ripple function. If the circuit is operated in continuous current mode with a duty ratio 6, the volt-seconds balance equation for L is given by: V)-(1-8) V =0 - dc OSV (1-8) V = 0 0 O 8(V-V)-SV = 0 dc ic O SV - (1-8) V = 0 1₂ C RL V
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