Please answer in typing format The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistorand the 5 nF capacitor is replaced by a 100 pF capacitor.Part AWhat is the scaled value of inductor?Figure300u(t) V1 of 1☐ΜΑUnitsL= ValueSubmitRequest AnswerPart B?Choose the correct expression for v, in the scaled circuit?Vo=(256e-400000tvo (256e 400000=Vo= (4e+4e-100000+)u(t) V-4e-100000+)u(t) V-400000t256e-100000+)u(t) VVo= (4e 400000+ +256e-100000+)u(t) V4 ΚΩ21 ΚΩwww+SubmitRequest Answer+Vo80 mH5 nFi.Provide Feedback

Step 1:Part AWe have to find scaled value for inductor and resistor R2 if scaled values of…

Answered: The circuit in (Figure 1) is scaled so…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

We have a system with 6 open-loop poles: { -1, -2, -1±2j, ±j } and a zero: { -3 } Draw the Root-Locus graph to show the change of system root locations for K≥0. Please draw the graph exactly. Don't tell me how to draw.
The initial value of the voltage v in the circuit is zero,and the initial value of the capacitor current, ic(0+), is 45 mA. Theexpression for the capacitor current is known to beic(t)=A1e−200t+A2e−800t, t≥0+,when R is 250 Ω. Find1. the values of α, ω0, L, C, A1, and A2(Hint:diC(0+)dt=−diL(0+)dt−diR(0+)dt=−v(0)L−1RiC(0+)C)1. the expression for v(t), t≥0,2. the expression for iR(t)≥0,3. the expression for iL(t)≥0
a series r-c circuit takes a current whose equation is i=0.85sin(754t+pi/4) when connected to a source of emf having the equation e=340sin754t. calculate the capacitance of the capacitor, circuit power factor, and power.
In the circuit given below, R = 14 Ω. The switch in the circuit moves from position A to position B at t = 0 (please note that the switch must connect to point B before it breaks the connection at A, a make-before-break switch). Determine i(t) for t > 0. a) i(t) = e–3.571t (0.726 sin(19.679t)) A b) i(t) = e–3.571t (4 cos(19.679t)) A c) i(t) = e–3.571t (4 cos(19.679t) – 0.726 sin(19.679t)) A d) i(t) = e–3.571t (4 cos(19.679t) + 0.726 sin(19.679t)) A
) Below, the circuit given in Figure 1 will be analyzed in the s definition region.a) Obtain node equations and additional equations for the specified nodes.b) VRy (t) for R1 = 1Ω, RY = 1Ω, e (t) = βu (t), C = 2F, L = 1H, vc (0) = 1V, iL (0) = 2ACalculate the voltage.β=8,a=3
After being open for along tike, the switch in the circuit is closed at t = 0 For t > 0 find a) Vc (t) b) i_sw (t) Current source 10mA Inductor 1.6H Resistor 20kohm Capacitor 5nF
Calculate the ratio vC/vT. Enter your answer rounded to 2 decimal places. All capacitors were initially discharged.at t = 0, S1 is placed at position 1 and S2 is closed.At t = 15 ms, S1 is placed at position 2 and S2 is kept closed.At t = 25 ms, S1 is kept at position 2 and S2 is opened.Data: V1 = 17 V;R1 = 3.5 kΩ, R2 = 6 kΩ, R3 = 1.5 kΩ, R4 = 2 kΩ, R5 = 19 kΩ, R6 = 10.5 kΩ;C1 = 4.0 µF, C2 = 4.0 µF, C3 = 12 µF
System Dynamics and Control The characteristic equation of a closed loop system is: s5+s4+2s3+s2+20s+12s5+s4+2s3+s2+20s+12 Use Routh-Hurwitz criteria and determine if the system is stable or not. Complete the Routh array; show all steps of your solution and determine the number of stable and unstable roots.
L1 = 12mH, L2 = 18mH, L3 = 10mH. R1 = 12kΩ, R2 = 20kΩ, R3 = 30kΩ, R4 = 8kΩ, R5 = 5kΩ, R6 = 12kΩ. The circuit is in dc steady state. Assume that circuit analysis has revealed that I1 = 0.5mA. Determine I2. Enter your answer in mA rounded to two decimal places. If the sign is negative, please be sure to include the negative sign.
With regard to the place of roots of the system of figure 1. Determine the values of K for the sistem to be stable. the angles of the asymptotes P1 = starting point (intersection) of the asymptotes P2 = Point of instersection, of the asymptotes, with the imaginary axis P3 = Points of arrival of the poles to the zero. P4 = The intersections of the imaginary axis ∝ = the departure angle (departure) of the conjugate poles.
A series RL circuit with R = 39 Ω has a constant voltage E = 168 V applied at t = 0 by the closing of a switch. Find L if at t = 1.15 s, i = 2.27 A.
given the circuit below , find and plot the current ix(t) for t>0s A=3A resistors=2 ohms each anc capacitor=1/4F voltage source is 3ix. solve in great detail.

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