The combustion of ammonia in the presence of oxygen yields NO2 and H2O: 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(g) The combustion of 58.78 mol of ammonia produces g of NO2

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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
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The combustion of 58.78 mol of ammonia produces

The combustion of ammonia in the presence of oxygen yields NO2 and H20:
4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(g)
The combustion of 58.78 mol of ammonia produces
g of NO2
Transcribed Image Text:The combustion of ammonia in the presence of oxygen yields NO2 and H20: 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(g) The combustion of 58.78 mol of ammonia produces g of NO2
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