The compaction of a soil obtained from a standard compaction test is shown in the attached figure. At OMC (optimum moisture content) the degree of saturation = 93 %. What is the highest possible dry unit weight for this soil to have when the moisture content is 9 %? Р 20.01 (1+w) 1 1 1 Pa(5₂) = 1 19.5 3 19.0 19 E N/m²] -L 1+ G.P wG. S₁

The compaction of a soil obtained from a standard compaction test is shown in the attached figure. At OMC (optimum moisture content) the degree of saturation = 93 %. What is the highest possible dry unit weight for this soil to have when the moisture content is 9 %? Р 20.01 (1+w) 1 1 1 Pa(5₂) = 1 19.5 3 19.0 19 E N/m²] -L 1+ G.P wG. S₁

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter3: Weight-volume Relationships And Plasticity

Section: Chapter Questions

Problem 3.5P

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The following results are obtained from standard compaction test for a soil, if Gs = 2.5 Water Content (%) 6.2 8.1 9.8 11.5 12.3 13.2 Unit weight (kN/m3) 16.9 18.7 19.5 20.5 20.4 20.1 Required: 1- The optimum water content (Wc %) 2- The maximum dry unit weight ( dry ) 3- The void ratio (e) 4- Degree of saturation (S %) 5- Find the weight of water needed to be added to 1 m3 to reach 100% saturation.
8 The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.24 kg Water content = 12.01% Max. dry unit weight from a laboratory compaction test = 19.70 kN/m3 Determine the relative compaction, in percent. Round off to two decimal places. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
The following are results of a field unit weight determination test using sand cone method: Volume of hole= 0.0015 m^3 Mass of moist soil from hole = 3.07 kg Water content = 12.24% Maximum dry unit weight from a laboratory compaction test = 19.28 kN/m^3 Determine the relative compaction, in percent.
The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
A proctor compaction test was conducted on a soil sample, and the following observations weremade:Water content, percent 7.7 11.5 14.6 17.5 19.7 21.2Mass of wet soil, g 1739 1919 2081 2033 1986 1948 1. determine the wet density in g/cm32. determine the dry density in g/cm33. determine the dry unit weight in kN/m34. construct the compaction curve 5. determine the optimum moisture content in percent 6. determine the maximum dry density in kN/m37. construct the 80% and 100% saturation lines using w% = 8, 12, 16, 20, and 24 8. calculate the saturation for the maximum dry density (ϒdmax in kN/m3) and the optimummoisture content (wopt %)
7. The relative compaction of a sand in the field is 94%. Given that dry unit weight max = 16.2 kN/m3 and dry unit weight min = 14.9 kN/m3 . For the field conditions. What is the relative density compaction? (Ans: 27%) What is the dry unit weight? (Ans: 15.23 kN/m3) What is the moist unit weight at a moisture content of 10%? (Ans: 16.45 kN/m3 )
Refer to Problem 3.8. Determine the mass of water (in kg) to be added per cubic meter (m3) of soil fora. 90% degree of saturationb. 100% degree of saturation 3.8 The dry unit weight of a soil sample is 14.8 kN/m3. Given that Gs = 2.72 and w = 17%,determine:a. Void ratiob. Moist unit weightc. Degree of saturationd. Unit weight when the sample is fully saturated
4. An in-situ soil sample weigh 25 kg of 0.02 cubic meter with a moisture content of 7% and specific gravity of 2.8. Determine the following: Moist Unit Weight, Dry Unit Weight, Moist Density, Dry Density, Void Ratio, Porosity, and the Degree of Saturation. (Calculate the Unit Weight and Density in Metric and English Units).
3.4 For a given soil, the following are known: Gs 5 2.74, moist unit weight, 5 20.6 kN/m3, and moisture content, w 5 16.6%. Determine:a. Dry unit weightb. Void ratioc. Porosityd. Degree of saturation3.15 Refer to Problem 3.14. Determine the mass of water, in kg, to be added per cubic meter (m3) of soil fora. 90% degree of saturationb. 100% degree of saturation
For a given soil sample, n= 0.43 and G₁ = 2.66. Calculate the dry unit weight and degree of saturation. Show complete solutions.
1. A soil sample has a volume of 5400 cm^3 and mass of 10.45 kg, and the water content of the soil is w = 11%. Determine (a) unit weight , dry unit weight , saturated unit weight, (b) void ratio and porosity, (c) degree of saturation (assume Gs=2.7).
The relative compaction of a sand in the field is 93.5%. Given the dry unit weight maximum= 16.98 kN/m3 and the dry unit weight minimum = 14.46 kN/m3. What is the water content of the sand in percent if the moist unit weight is 18.42 kN/m3? a.17.1 b.16.0 c.15.2 d.14.3