The content of a part of MIPS memory and the contents of three registers are provided below. Answer the following questions?
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Suppose a specific MCU has the following size of memories: 2 M byte of flash, starting from 0x0800_0000, 256 k byte of SRAM starting from 0x2000_0000, and 8 k byte registers for GPIOs, start at 0x4001_0000. (Note that 0x is the prefix for hexadecimal numbers.) Draw the memory map based on your calculations for the addresses.Question 2: Write the MIPS code for the given Hexadecimal Machine Code that starts at memory address 0x40000. Line1: 0x0080082A Line2: 0x14200002 Line3: 0x2084FFFF Line4: 0x08010005 Line5: 0x20840001 Line6: 0x1480FFFA Line7: 0x03E00008 Line8: 0x0C010000
- The 8-bit registers R1, R2, R3, and R4 initially have the following values: R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. R1 <-R1 + R2 R3<- R3 ^ R4, R2 <- R2 + 1 R1 <- R1 R3Q2. The 8-bit registers AR, BR, CR, and DR initially have the following values: AR= 11010010, BR= 11100011, CR= 10111001 , DR= 10101011 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR <-AR + BR CR <- CR ^ DR, BR <- CR + 1 AR <-AR – CR3) The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequenceof microoperations.AR AR + BR Add BR + ARCR CR AND DR, BR BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR
- Consider the following store instruction: SW R1, 0x000F(R0). Assume that the registers R0 and R1 are initialized with 0x00000001 and 0x53A78BC Frespectively. A section of the MIPS byte addressable data memory is shown. Give the memory word of the following memory locations after the SW operation: (a). 0x00000015. (b). 0x00000014. (c). 0x00000013. (d) 0x00000012.(e). 0x00000011. (f). 0x00000010.Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
- Considering the following MIPS assembly code snippet. mydata: .word 0x01020304, 0x05060708, 0x090A0B0C0, 0x0D0E0F10, 0xE0001211, 0xA031023A … li $t1, 1 sll $t1, $t1, 2 lb $s0, mydata($t1) What is the value of register $s0 after the instruction lb was executed? _________ Please provide an answer and an explanation.Show how the following values would be stored by machines with 32-bit words, using little endian and then big endian format. Assume each value starts at address 1016. Draw a diagram of memory for each, placing the appropriate values in the correct (and labeled) memory locations. 1234567816 ABCDEF1216 8765432116Suppose that a 4M × 32 main memory is built using 128K × 8 RAM chips and memory is word addressable (word size = 32 bits)a. How many RAM chips are needed?b. How many chips would be involved when accessing a full word?c. How many banks will this memory have?d. How many address bits are needed for the whole main memory?e. If high-order interleaving is used, where would the address 7060016 be located (in which bank)?f. If low-order interleaving is used, where would the address 2C77D516 be located?