The content of registers and memory are summarized as follow: R0=0x24682244 R1=0x00446688 R2=0x00118822 R3=0X00000077 R4=0x4000000C R5=0x00000008 R6=0x00000055 R7=0x40000000 R8=0x40000002 (0x40000000)= 12 84 56 78 90 AB CD EF 11 22 33 44 55 66 77 88 Evaluate the following program and obtain the new content of the registers R0 – R7, and new content of memory starting from address 0x40000000 until 0x4000000F ENTRY MOVS R0,#25 LDRB R1,[R7] LDRH R2,[R7,#0x2] LDR R3,[R7] LDRSB R4,[R7,R5] LDRSH R5,[R8,R5] STR R6,[R7],#4 STRB R7,[R8,#1]! STM R7,{R1,R5-R6} STRH R0,[R8,#5] END

Systems Architecture
7th Edition
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter4: Processor Technology And Architecture
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Problem 2PE: If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the...
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  • The content of registers and memory are summarized as follow:

 R0=0x24682244  R1=0x00446688  R2=0x00118822  R3=0X00000077

 R4=0x4000000C  R5=0x00000008  R6=0x00000055  R7=0x40000000

 R8=0x40000002

 

(0x40000000)= 12 84 56 78 90 AB CD EF 11 22 33 44 55 66 77 88

 

Evaluate the following program and obtain the new content of the registers R0 – R7, and new content of memory starting from address 0x40000000 until 0x4000000F

          ENTRY

MOVS      R0,#25

LDRB      R1,[R7]

LDRH      R2,[R7,#0x2]

LDR       R3,[R7]

LDRSB     R4,[R7,R5]

LDRSH     R5,[R8,R5]

STR      R6,[R7],#4

STRB      R7,[R8,#1]!

STM       R7,{R1,R5-R6}

STRH      R0,[R8,#5]

END

 

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