The cube in Figure 23-27 has edge length 1.40 m and is oriented as shown in a region of uniform electric field. Find the electric flux through the right face for the following electric fields, given in newtons per coulomb. Fig. 23-27 (a) 4.00 i N•m?/c (b) -7.00 j N•m2/C (c) -3.00 i + 6.00 k |N•m²/c

Q: *16 O The box-like Gaussian surface shown in Fig. 23-38 en- closes a net charge of +24.0eo C and…

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Q: A circular surface is in a uniform electric field region with strength of 2.40 N/C. If the surface…

A: Introduction Given information- Magnitude of electric field E = 2.40 N/C Radius of circular surface…

Q: An area vector with magnitude of 2.50 m², has a normal oriented along the direction î +}+ k. The…

A: Electric flux :-  The number of the electric force of lines that passing through the certain area is…

Q: 65 In Fig. 22-64a, a particle of charge +Q produces an electric field of magnitude Epart at point P,…

A: Given: Electric field at a distance R of charge Q = Epart. Let the charge density over arc = λ.

Q: 4 Figure 23-24 shows, in cross sec- tion, two Gaussian spheres and two Gaussian cubes that are…

A: so the order of ranking according to the net flux according to the net flux through the gaussian…

Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.450 m and 0.675 m. The sheet is…

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Q: A very large conducting plate lying in the xy plane carries a charge per unit area of 70. A second…

A: The direction of electric field due to the plates are as shown in figure .E1 is the electric field…

Q: What is the magnitude of the electric flux through the rectangle if E = (120î – 1903) N/C? Express…

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Q: Find the electric flux ( in units of N.m /C) through the surface of the rectangle ( 30 cm x 40 cm)…

A: Given : Area (A) = 30 cm x 40 cm = 1200 cm = 0.12 m2 E = 386.3 N/C  θ = 30°

Q: •34 In Fig. 23-45, a small circular hole of radius R = 1.80 cm has been cut in the middle of an…

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Q: 7 SSM ILW www In Fig. 22-35, the TO91 four particles form a square of edge 92 41 = +10.0 nC, 92 =…

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Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

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Q: 87 In Fig. 22-69, particle 1 of charge q1 = 1.00 pC and particle 2 of charge q2 = -2.00 pC are fixed…

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Q: •5 In Fig. 23-33, a proton is a dis- tance d/2 directly above the center of a square of side d. What…

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Q: Find the electric flux (in units of N.m2/C) through the surface in the figure ( dashed line) given…

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Q: The Earth possesses an electric field of (average) magnitude 150 N/C near its surface. The field…

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Q: 49 In Fig. 23-54, a solid sphere of radius a = 2.00 cm is concentric with a spherical conducting…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: GO •54 In Fig. 22-61, an electron is shot at an initial speed of vo = 2.00 x 100 m/s, at angle 0o =…

A: given V = 2.00 x 106 m/s θ=400  Using E→ = (5.00N/C)j^ ↑ Force on electron due to electric field =…

Q: 44 Figure 23-52 gives the magni- tude of the electric field inside and outside a sphere with a…

A: Electric field at the surface of the solid sphere is maximum & from the graph, maximum value of…

Q: Calculate the flux through a square plate 1.0 m on a side inclined at 120° with respect to a…

A: Flux is given by ϕ=EAcosθwhere θ is angle between area vector(normal to plane) and electric field

Q: Calculate the flux through a square plate 1.0 m on a side inclined at 120° with respect to a…

A: Given that, Electric field = 100 N/C Inclined angle = 120° Side of plate = 1.0 m

Q: An electric field given by E = 3.5 i - 3.0(y2 + 2.0) j pierces the Gaussian cube of Figure 23-05. (E…

A: according to guideline we need to solve only first three sub part. Given that   E = 3.5 i - 3.0(y2…

Q: A pyramid with hori2ontal square base, 6.00 m on each side, anda height of 4.00 m is placed in a…

A: Ans:- Image-1

Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.2 m and 1.7 m. The sheet is…

A: Given that Length of the sheet L = 1.7 m Width of the sheet b = 0.2 m Uniform electric field E = 65…

Q: 6) A uniform electric field with a magnitude of 5 x 106 N/C is applied to a cube of edge length 0.1…

A: magnitude of electric field is E = 5*106 N/C cube of edge length is L = 0.1m the direction of…

Q: A very large conducting plate lying in the xy plane carries a charge per unit area of 30. A second…

A: Electric field for large conducting plate is given by: E=σ2εo Given: charge per unit area of xy…

Q: Equation 23-11 (E = s/´0) gives the electric field at points near a charged conducting surface.…

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Q: An area vector with magnitude of 3.48 m^2 , has a normal oriented along the direction ˆi + ˆj + ˆk.…

A: Given in question: Magnitude of area vectorA→ = 3.48 m2                                  The…

Q: •27 Go In Fig. 22-51, two curved plastic rods, one of charge +q and the other of +4 charge -q, form…

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Q: Figure 22-32 shows two harged particles on an x axis: -q = --3.20 x 10-19 C at x = -3.00 m and g=…

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Q: In Figure 23-35, short sections of two very long parallel lines of charge are shown, fixed in place…

A: The electric field due to line 1 is The electric field due to line 2 is

Q: A disk of radius 0.10 m is oriented with its normal unit vector îî at 30° to a uniform electric…

A: Radius of the disk r=0.1 m, magnitude of the uniform electric field E=2*103N/C and angle the area…

Q: Compute the electric flux of the following sets of variables: 1. E-72x10 N/C 3. E=9.7 x 10 N/C A =…

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Q: Find the electric flux (in units of N.m /C) through the surface of the rectangle (30 cm x 40 cm) in…

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Q: An electric fieldĒ =aî+Bj +yk exists in space, where a, B. y are constants. Magnitude of electric…

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Q: 30 In Fig. 23-43, short sections of two very long parallel lines of charge are shown, fixed in…

A: By condition,

Q: 25.0 N/C 20.0 N/C. 20.0 N/C 35.0 N/C 20.0 N/C 15.0 N/C Assume the magnitude of the electric field on…

A: Data Given ,  Side of the cube ( L ) = 10.62 m  From the given figure ,  The direction of Electric…

Q: Rank these five surfaces in order of the electric flux through them, from most positive to most…

A: From gauss law  Electric flux = Qnet /eo Qnet= net charge enclosed by any surface eo = permittivity…

Q: A point charge (m = 1.0 gram) at the end of an insulating cord of length 55 cm is observed to be in…

A: Given values: Mass of the point charge, m=1 g Length of the cord, l=55 cm Electric field, E=9500 N/C…

Q: •29 Figure 22-47a shows a nonconducting rod with a uniformly dis- tributed charge +Q. The rod forms…

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Q: A proton is enclosed by a closed Gaussian surface. Find the magnitude of the electric flux through…

A: The charge of a proton particle is, q=1.6×10-19 C

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.