The current world record for the men's marathon (a distance of 42.195 km) is 2 hours 2 minutes and 57 seconds. Find the average speed. _nswer:- 5 20.59 kmh¹
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- i need a step by step detail on how to get part b* thank you so much! b) calculate thw magnitude (in km/h) and direction (in degrees north of east) of the hikers average velocity during the given time.Physics HW need help ，how did you find the speed for question 5？1Just answer number one (I need handwritten cursive answers and no plagiarism i will double check ty i hope you follow)
- NO NEED TO SHOW ANY WORK JUST FINAL ANSWER AS QUICKLY AS POSSIBLE! I read the honor code and it says that a question can have up to 3 subparts (i.e. part a, b, c and d). Question: What was the approximate acceleration, in m/s^2, during the burning of the rocket? Sub questions: a. At what time, in seconds, does the rocket reach its maximum height? b. What is the velocity of the rocket, in m/s, just as it reaches its maximum height? c. What is the maximum altitude, in meters, reached by the rocket? d. What is tf?From part a, can you write it in a paper, because i cant understand how you get 9. Thank youI'm pretty sure I got the first step right, but I'm really struggling with the second step. I think I set up the equation correctly, but when it comes to actually solving, I'm not getting the steps right. Can you please list out step by step how to solve the equation in part 2, assuming I got that equation right. I've attached the problem, as well as my work.
- Answer part b only thank youPlease can you help me with these questions? 1) A massive space freighter wants to accelerate at 1g. It takes time for the rocket engines to rev up, and turn up to their desired power. The freighter starts from rest, and its acceleration (until it reaches 1g) is: "refer to the picture". The captain wants to reach 1g at time t = T. What must A be, to satisfy a(T) = 1g? 2) The desired final acceleration is now 4g, with a corresponding value for A. Recall the equation in the picture. Acceleration feels like a weight, and a rapid change in acceleration feels like a rapid change in weight. You don't want a too rapid change in weight -- the derivative a'(t) shouldn't be too great. Therefore find T (in seconds) such that the maximum value of a'(t) is 1/80 m/s3. 3) Now, A = 0.6 and T = 2800 seconds. The freighter begins at rest and reaches the desired acceleration in time T. Now calculate and answer v(T) in m/s. Thank you.As a technical engineer in the army, you are part of a team in charge of testing and commissioning a new tankrecently purchased by the artillery.Field testing has revealed the following information:1) The tank moves from rest to a speed of 70 ??/ℎ? in 10 seconds.2) Using the breaking system, the tank is brought to a complete stop from a speed of 70 ??/ℎ? in 5 seconds.You are required to address all the questions below providing all calculations, graphs, and explanations asappropriate to back your answers The tank is to be placed on a hill that is 1 km high above the ground. The enemy’s base is located at a horizontaldistance of 10 km away and it is in a valley 0.5 km below the ground. Air resistance is neglected. Gravitationalacceleration is constant and equal to 9.8?/?2 downwards.a) If the bomb is to be fired perfectly horizontally, what should the launching speed of the bomb be in order tohit the target?b) What is the duration it would take the bomb to hit the target?c) Find x(t) and…