The curve given by the polar equation r = a(1– cos ) is called a The cardioid has equation (22 + y? + ax)2 = a² (x? +y?) %3D To sketch the graph of r = 4(1 – cose) we first observe that if a point (r,0) lies on the graph then lies also on the same graph. This shows that the graph is symmetric about the |. If e is . Similarly, if 0 is Therefore, it suffices to let change between 0 and then r is 0. Next, we compute the values of r for increasing values of 0. If 0 is then r is approximately then r is Also if e is then r is approximately In the case of 8=Tt/2 we have r=4 because is zero. If 8 is we have r is Also, if 0=5Tt/6 then r is approximately Finally, r is when e is t. ja trom h m 0.54 2n/3 Cartesian у-ахis (r,-0) 6. 26 Tt/4 cosine T/3 cardioid the line y=x+2 Tt/6 1.17 7.46 х-ахis 2 8

Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter8: Complex Numbers And Polarcoordinates
Section: Chapter Questions
Problem 7GP
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The curve given by the polar equation
r = a(1 – cos )
is called a
The cardioid has
equation
(22 + y? + ax)2 = a² (x? +y?)
To sketch the graph of
r = 4(1 – cose)
we first observe that if a point (r,0) lies on the graph then
lies also on the same graph. This shows that the graph is symmetric about the
. If e is
. Similarly, if 0 is
Therefore, it suffices to let
change between 0 and
then r is 0. Next, we compute the
values of r for increasing values of 0. If 0 is
then r is approximately
then r is
Also if e is
then r is approximately
In the case of 8=T/2 we have r=4 because
is zero. If 8 is
we
have r is
Also, if 0=5Tt/6 then r is approximately
Finally, r is
when e is n.
ja trom b h m
0.54
2/3
Cartesian
y-axis
(r,-0)
6.
26
Tt/4
cosine
T/3
cardioid
the line y=x+2
Tt/6
1.17
7.46
х-аxis
2
8
Transcribed Image Text:The curve given by the polar equation r = a(1 – cos ) is called a The cardioid has equation (22 + y? + ax)2 = a² (x? +y?) To sketch the graph of r = 4(1 – cose) we first observe that if a point (r,0) lies on the graph then lies also on the same graph. This shows that the graph is symmetric about the . If e is . Similarly, if 0 is Therefore, it suffices to let change between 0 and then r is 0. Next, we compute the values of r for increasing values of 0. If 0 is then r is approximately then r is Also if e is then r is approximately In the case of 8=T/2 we have r=4 because is zero. If 8 is we have r is Also, if 0=5Tt/6 then r is approximately Finally, r is when e is n. ja trom b h m 0.54 2/3 Cartesian y-axis (r,-0) 6. 26 Tt/4 cosine T/3 cardioid the line y=x+2 Tt/6 1.17 7.46 х-аxis 2 8
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