The degree of a polynomial function ) IS The function has roots of multiplicity 2 at x = -3 and x = 2 and a root of multiplicity 1 at x = -2. The graph has y-intercept (0, 8). What is the equation of the function? Os) = {(x - 3)°(x+ 2)° (x – 2) Os) = }(x + 3)²(x – 2)° (x + 2) Os = (x + 3)°(x – 2)² (x + 2) %3D Orm=x+3°ox – 2)²

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.5: Complex Zeros And The Fundamental Theorem Of Algebra
Problem 3E: A polynomial of degree n I has exactly ____________________zero if a zero of multiplicity m is...
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The degree of a polynomial function f is 5.
The function has roots of multiplicity 2 at x = -3 and x = 2 and a root of multiplicity 1 at x = -2.
The graph has y-intercept (0, 8).
What is the equation of the function?
OSx) = }(x – 3)°(x+2)° (x – 2)
OS) = }(x + 3)²(x – 2)° (x + 2)
Os(x) = }(x + 3)²(x – 2)² (x + 2)
Or=x+3°(x – 2)²
Os = -(x + 3)°(x - 2)° (x + 2)
Os) = (x + 3) (x + 2) (x + 2)
Transcribed Image Text:The degree of a polynomial function f is 5. The function has roots of multiplicity 2 at x = -3 and x = 2 and a root of multiplicity 1 at x = -2. The graph has y-intercept (0, 8). What is the equation of the function? OSx) = }(x – 3)°(x+2)° (x – 2) OS) = }(x + 3)²(x – 2)° (x + 2) Os(x) = }(x + 3)²(x – 2)² (x + 2) Or=x+3°(x – 2)² Os = -(x + 3)°(x - 2)° (x + 2) Os) = (x + 3) (x + 2) (x + 2)
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