The density of a spherical solid at a point P = (x, y, z) is given by f(x, y, z) = c(x² + y² + z²) , c it is a positive constant. When attempting a displacement from the point P = (1,2,3) of the interior of this solid, according to the vector below:   a = (1, 1/2, -1)   The density trend is:    A) decrease  B) increase to the maximum  C) keep constant  D) decrease to the maximum  E) increase

icon
Related questions
Question

The density of a spherical solid at a point P = (x, y, z) is given by f(x, y, z) = c(x² + y² + z²) , c it is a positive constant. When attempting a displacement from the point P = (1,2,3) of the interior of this solid, according to the vector below:

 

a = (1, 1/2, -1)

 

The density trend is:

 

 A)

decrease

 B)

increase to the maximum

 C)

keep constant

 D)

decrease to the maximum

 E)

increase

Expert Solution
Density at point P(1,2,3)

The density of spherical solid at any point P(x,y,z) is given by, 

Advanced Physics homework question answer, step 1, image 1

Therefore, the density at point P(1,2,3) is,

Advanced Physics homework question answer, step 1, image 2

 

Coordinates of the new location

The vector from point A(x1,y1,z1 ) to vector B(x2,y2,z2) is given by,

Advanced Physics homework question answer, step 2, image 1

The displacement is from point P(1,2,3) to some point say P'(x2,y2,z2) along the vector a(1,1/2,-1), then, 

Advanced Physics homework question answer, step 2, image 2

The new location after displacement along vector a is P'(2,5/2,2).

steps

Step by step

Solved in 4 steps with 6 images

Blurred answer