The derivative of the function y = xe(5+sec(2x)) is: y' [1+ 2x sec(2x) tan(2x)Je(*ece(2x) y' [1+x sec(2x) tan(2x)]e5+secc2)) the above the above y= [1- 2x sec(2x) tan(2x)Je+see(2x) y' =[1-x sec(2x) tan(2x) Je+se(0) the above the above

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The derivative of the function
y = xe(5+sec(2x)) is:
y' [1+ 2xsec(2x) tan(2x)]e(*+sec(2x)
y' [1+x sec(2x) tan(2x) Je+secc2))
O the above
the above
y' = [1- 2x sec(2x) tan(2x)]e5+see(2x)
y' [1-x sec(2x) tan(2x)]e5+see(20)
O the above
O the above
Transcribed Image Text:The derivative of the function y = xe(5+sec(2x)) is: y' [1+ 2xsec(2x) tan(2x)]e(*+sec(2x) y' [1+x sec(2x) tan(2x) Je+secc2)) O the above the above y' = [1- 2x sec(2x) tan(2x)]e5+see(2x) y' [1-x sec(2x) tan(2x)]e5+see(20) O the above O the above
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