10.The diagram below shows two charges Q,and Q, situated 24 mm apart. P is a point onthe line joining the two charges and is 10 mmaway from Q,.Q = +40 nCPQ =+30 nC%3D- 10 mm- 24 mmDetermine the resultant electric field (magni-tüde and direction) at P.

Given data: Q1 = +40 nC = +40 × 10-9 C Q2 = +30 nC = +30 × 10-9 C Distance between charges = 24 mm…

The diagram below shows two charges Q, and Q, situated 24 mm apart. P is a point on the line joining the two charges and is 10 mm away from Q,. 2 Q, = +40 nC 0, = +30 nC %3D %3D -- 10 mm - -- 24 mm Determine the resultant electric field (magni- tüde and direction) at P.

The diagram below shows two charges Q, and Q, situated 24 mm apart. P is a point on the line joining the two charges and is 10 mm away from Q,. 2 Q, = +40 nC 0, = +30 nC %3D %3D -- 10 mm - -- 24 mm Determine the resultant electric field (magni- tüde and direction) at P.

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Continuous Charge Distributions And Gauss's Law

Section: Chapter Questions

Problem 27P: A large, flat, horizontal sheet of charge has a charge per unit area of 9.00 C/m2. Find the electric...

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Question

10.
The diagram below shows two charges Q,
and Q, situated 24 mm apart. P is a point on
the line joining the two charges and is 10 mm
away from Q,.
Q = +40 nC
P
Q =+30 nC
%3D
- 10 mm
- 24 mm
Determine the resultant electric field (magni-
tüde and direction) at P.

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