Part 31. The diameter of the Sun is 1,391,400 km. The diameter of the Moon is 3,474.8 km. Findthe ratio, r= Dsa/Dsvan between the sizes.2. From the point of view of an obs erver on Eanth (consider the Earth as a point-like object),during the eclipse, the Moon covers the Sun exactly. Sketch a picture to illustrate thisfact. Use a nuler to get a straight line. Your drawing does not need to be in scale.3. The Sun is 1 Astronomical Unit (AU) away from the Earth. Find the distance between theEarth and the Moon in AU's using the ratio of similar triangles. Show your work.DEM=AU.Convert this to kilometers. Use 1 AU = 149,600,000 km.DEM =km.

We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Answered: The diameter of the Sun is 1,391,400…

The diameter of the Sun is 1,391,400 km. The diameter Moon is 3,474.8 km. Find of the the ratio, r= Dsa/DMn between the sizes.

Astronomy

1st Edition

ISBN:9781938168284

Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Publisher:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Chapter17: Analyzing Starlight

Section: Chapter Questions

Problem 38E: Do the previous problem again, this time using the information that the Sun is 150,000,000 km away....

See similar textbooks

Similar questions

If you observed the Solar System from the nearest star (distance = 1.3 parsecs), what would the maximum angular separation be between Earth and the Sun? (Note: 1 pc is 2.1105 AU.) (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)
To determine the diameter of the sun an astronomer might sight with a transit (a device used by surveyors for measuring angles) first to one edge of the sun and then to the other, estimating that the included angle equals 32'. Assuming that the distance d from Earth to the sun is 92,919,800 mi, approximate the diameter of the sun.
1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec USE 1.7 arcsec NOT 2.946 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of error
- How far (in km) is 3.5 lightyears(ly) – the distance traveled by light in one Earth year? - How much is this same value in parsecs and (C) in astronomical units (AU)? Use 299,732 km/s for the speed of light (c) and 1 year = 365 days. Show your solution and write your answer in both regular notation and scientific notation.
1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of error
Calculate by how many times Betelgeuse is brighter than the Sun, if its parallax is 0.006 arcsec, and its apparent magnitude is m = +.5. Can you first use the parallax to calculate the distance and then use the magnitude-distance formula to find the absolute magnitude of Betelgeuse and finally, compare it to the absolute magnitude of the Sun which is -26,74 because other experts used other methods and the answer was not correct.
Earth is about 150 million kilometers from the Sun (1 Astronomical Unit, or AU), and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Using these two facts and the inverse square law for light, determine the apparent brightness that we would measure for the Sun if we were located at the following positions. a) At the orbit of Jupiter (780 million km from the Sun).
1- MODIS is an Earth Observation sensor onboard TERRA spacecraft flying in a near-polar circular orbit with an orbital period of 98.8 minutes. The width of the swath imaged by MODIS is 2330 km. A- How many orbits does TERRA trace in one day? B- Assuming that the Earth rotates around its polar axis at a rate of 0.2618 rd/hr and that the equatorial radius is 6378 km, do two consecutive swaths of MODIS overlap at the equator? (hint: the length of an arc = angle in rd * radius) C- The radius of the latitude circle at 35 deg is 5224.5 km. Do two consecutive swaths of MODIS overlap at latitude 35 deg? 2- An aerostationary orbit for Mars is equivalent to a geostationary orbit for Earth. It is designed to enable a satellite in that orbit to image always the same surface of Mars. Calculate the altitude of an aerostationary orbit assuming that Mars is spherical, that its sidereal rotational period is 1.02595676 Earth days, its equatorial radius is 3389.50 km and its mass is…
How do we know the age of the Sun?
What are the three basic components of a modern astronomical instrument? Describe each in one to two sentences.
How Do We Know? Why is it important that a theory make testable predictions?
Confirm that the angular diameter of the Sun of 1/2° corresponds to a linear diameter of 1.39 million km. Use the average distance of the Sun and Earth to derive the answer. (Hint: This can be solved using a trigonometric function.)