The difference of any two odd integers is even. Proof: Let m and n be any odd integers. By definition of odd, there are integers r and s so that m can be expressed in terms of r and n can be expressed in terms of s as follows. m = n = Write m - n in terms ofr and s and factor out a 2 to obtain m - n = is an integer because differences of integers are integers. Now Therefore, m - n = 2· (an integer), and so m - n is even by definition of even

Algebra and Trigonometry (MindTap Course List)
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ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
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ChapterP: Prerequisites
SectionP.6: Factoring
Problem 119E
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The difference of any two odd integers is even.
Proof: Let m and n be any odd integers. By definition of odd, there are integers r and s so that m can be expressed in terms of r and n can be expressed in terms of s as follows.
m =
n =
Write m - n in terms ofr and s and factor out a 2 to obtain m - n =
is an integer because differences
of integers are integers.
Now
Therefore, m - n = 2· (an integer), and so m - n is even
by definition of even
Transcribed Image Text:The difference of any two odd integers is even. Proof: Let m and n be any odd integers. By definition of odd, there are integers r and s so that m can be expressed in terms of r and n can be expressed in terms of s as follows. m = n = Write m - n in terms ofr and s and factor out a 2 to obtain m - n = is an integer because differences of integers are integers. Now Therefore, m - n = 2· (an integer), and so m - n is even by definition of even
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