A whole number a is odd if and only if there is a whole number k such that a = 2k +1. Use this representation of an odd number to prove that the square of a odd natural number leaves a remainder of 1 when divided by 4. O A. Every odd number can be written in the form 2k + 1 where k is any whole number. O B. The square of the starting number is divisible by 4. O c. The remainder of the square of the starting number divided by 4 is 1. O D. The starting number is odd.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 38E
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A whole number a is odd if and only if there is a whole number k such that a = 2k +1. Use this representation of an odd number to prove that the square of any
odd natural number leaves a remainder of 1 when divided by 4.
O A. Every odd number can be written in the form 2k + 1 where k is any whole number.
O B. The square of the starting number is divisible by 4.
O c. The remainder of the square of the starting number divided by 4 is 1.
O D. The starting number is odd.
Transcribed Image Text:A whole number a is odd if and only if there is a whole number k such that a = 2k +1. Use this representation of an odd number to prove that the square of any odd natural number leaves a remainder of 1 when divided by 4. O A. Every odd number can be written in the form 2k + 1 where k is any whole number. O B. The square of the starting number is divisible by 4. O c. The remainder of the square of the starting number divided by 4 is 1. O D. The starting number is odd.
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