The displacements for the truss shown in Figure P19.7 are U = 0.0 U2= 0.0 U4=-0.3333 U3= 1.748 Us=-0.5000 U6= 0.0 Us=-3.690 U7= 2.248 The area of each member in square centimeters is underlined. The ler dimensions are in centimeters and each member is made from steel, 20(106) N/cm?. Calculate the axial force in each member connecte joint two and show that this joint is in equilibrium. There is no temper= change. (4) 10 4 10 15 (3) 15 200- 500 (5) (1) (2) 10 3 1 2.
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- In the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa 1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar? a. 0.454 b. 0.9 c. 0.838 d. 0.869 2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2 a. 463.83 kN…A flange coupling connects two 2” diameter shafts. The flanges are fitted with 6 bolts of SAE 1040 steel on a 7” bolt circle. The shafts runs at 300 rpm and transmits 45 hp. Assume a factor of safety of 5, ultimate tension of 70,000 psi, and ultimate shear of 55,000 psi. Determine: a) The torque transmitted, in-lbs b) The force applied per bolt, lbs c) The diameter of the bolt required, in d) The thickness of flanged to be used, inMechanical design The maximum load in a rotating shaft is subjected to bending moment of 1 kN.m and a torque of 1 kN.m. The member is made of steel the Ultimate Tensile Strength 440 MPa, Yield Tensile Strength 370 MPa. With a safety factor of 4, kt = km = 1.5 and keyway stress consternation is presented. According to the maximum shear stress theory, the shaft diameter will be: a. 160 mm b. 74 mm C. 145 mm d. 92.5 mm e. 60 mm f. 66 mm
- A 4-T crane is used to lift a 3m x 1.2m x 200mm pre-cst panel. A preader beam is needed to ensure the proper distribution of load in the lifting chains. Consider modulus of elasticity, E=200,000 MPa, allowable shearing stress of lifting pin is 50 MPa, the steel plate used in the spreader beam has an allowable bearing stress of 40 MPa. (All measurement in the figure is in millimeters) 1. Determine the total load in kN, the crane has to carry the the lifting accessories (spreader beam, lifting chains and hooks) has a total mass of 720 kgs. if 2. Determine the average normal stress on each leg of the lifting chain A and B. 3. Determine the required diameter (d) in millimeters of the lifting pin if the allowable shearing stress must not be exceeded (Round to the nearest whole number). 4. Determine the required thickness (t) in millimeters of the steel plate to be used if the allowable bearing stress must not be exceeded. (Round to the neareat whole number)A bushed pin type flexible coupling is used to transmit 10 kW power at 720 rpm. The design torque is 150% of rated torque. The keys have square cross-section. The permissible stresses are: For shaft and key material, τ = 66.67 N/mm2 , σc = 200 N/mm2 ; For pin material, τ = 35 N/mm2 , σt = 133 N/mm2 ; For flange material τ = 16.67 N/mm2 . The permissible bearing pressure for rubber bushes is 1 N/mm2. The number of bushes is 4. Design the bushed pin flexible coupling. Explain Axle, Spindle, Counter shaft and line-shaft with their examples .A bushed pin type flexible coupling is used to transmit 10 kW power at 720 rpm. The design torque is 150% of rated torque. The keys have square cross-section. The permissible stresses are: For shaft and key material, τ = 66.67 N/mm2, σc = 200 N/mm2; For pin material, τ = 35 N/mm2, σt = 133 N/mm2; For flange material τ = 16.67 N/mm2. The permissible bearing pressure for rubber bushes is 1 N/mm2. The number of bushes is 4. Design the bushed pin flexible coupling.
- Compute the vertical displacement of joints B and C for the frame shown in Figure P8.30. Given: I = 360 in.4 , E = 30,000 kips/in.2 . Consider only flexural deformations.(5) A gas engine valve spring is loaded to 35kgf when the valve is closed & 52kgf hen the valve is open. The valve lift is 8mm. The outside diameter is to be from 38mm~45mm, & the permissible stress is 413N/mm2 . Determine: (a) the wire & outside diameter; (b) the number of effective coils; (c) the free length when it is squared & ground.The squared and grounded ends of a safety valve with 7.5 coils. The coils measure 105 mm in diameter on the outside and 17 mm wire diameter. It measures 210 mm in free length. 82 Gpa is the modulus of rigidity. Calculate the initial compression length of the wire required to maintain a boiler pressure of 1.35 Mpa on a 30 mm diameter valve seat. (Draw the diagram)
- A short timber post of Douglas fir is subjected to an axial compressive load of 40,000 lb. The nominal dimensions of the post area are 10 in. by 10 in. Its length is 8 ft. Assume a proportional limit of 6000 psi. Using dressed dimensions, compute (a) stress. (Unit: psi) A short timber post of Douglas fir is subjected to an axial compressive load of 40,000 lb. The nominal dimensions of the post area are 10 in. by 10 in. Its length is 8 ft. Assume a proportional limit of 6000 psi. Using dressed dimensions, compute (b) strain. A short timber post of Douglas fir is subjected to an axial compressive load of 40,000 lb. The nominal dimensions of the post area are 10 in. by 10 in. Its length is 8 ft. Assume a proportional limit of 6000 psi. Using dressed dimensions, compute (c) total deformation. (Unit: in)Design a typical rigid flange coupling for connecting a motor and a centrifugal pump shafts. The coupling needs to transmit 15 KW at 1000 rpm. The allowable shear stresses of the shaft, key and bolt materials are 60 MPa, 50 MPa and 25 MPa respectively. The shear modulus of the shaft material may be taken as 84GPa. The angle of twist of the shaft should be limited to 1 degree in 20 times the shaft diameter. Note: show complete solutionA shaft is designed to transmit power of 100 kW at 180 rpm. The allowable shear stress is 50MPa and modulus of rigidity of 80 GPa. The angle of twist is not to exceed to 1° in 4-meter length A. Calculate the diameter of the shaft in inches. B.If the shaft in A is to be fitted to a hub with material SAE 0105 and fit classification of FN3, what will be the maximum and minimum stresses based on the interference of metal.