((transmitted power = 0.050 MW, speed = 500 rpm, Modulus of Elast %3D GPa, Modulus of Rigidity = 70 GPa, Ultimate stress = 620 MPa, C %3D stress = 240 MPa, Yield stress = 440 MPa, Shear stress = 120 MPa %3D %3D %3D Bending moment = 0.5 KN m, diameter of rivet = 10 mm, pitch = 50 m %3D %3D For the 50 mm shaft shown in figure. 2. If a torque T and mor applied to the shaft, use the suitable theories to design the welding je the whole system.

((transmitted power = 0.050 MW, speed = 500 rpm, Modulus of Elast %3D GPa, Modulus of Rigidity = 70 GPa, Ultimate stress = 620 MPa, C %3D stress = 240 MPa, Yield stress = 440 MPa, Shear stress = 120 MPa %3D %3D %3D Bending moment = 0.5 KN m, diameter of rivet = 10 mm, pitch = 50 m %3D %3D For the 50 mm shaft shown in figure. 2. If a torque T and mor applied to the shaft, use the suitable theories to design the welding je the whole system.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Draw a shear and moment diagrams, step by step.
In drilling a deep oil well the drill shaft, consisting of sections of “drill rod”, is powered from the top, while the load or counter torque is taken off at the bottom. The drill hole is 3 1/2 miles deep. Assuming a solid drill rod of circular cross section and 1 in. diameter, designed to a working shear stress of 5,000 psi, turning at 700 rpm, calculate (a) The wind-up, i.e. the twist angle between the top and bottom. (b) The horsepower of the driving motor. (c) State all assumptions, and comment on the results. What other considerations may have to be taken into account in using this drill? NOTE: The shear modulus of steel may be taken as 12 x 106 psi. Also 1 mile = 5,280 ft.
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derive shear and moment equations
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