The distance s(t), in meters, is given as a function of time, in seconds, below. s(t)=t^5−2/t+ln(9t) Find the velocity function and evaluate at t=2 seconds. Answer in the form: v(t)=At^4+2t^B+t^−1. A= B= v(2)= Find the acceleration function and evaluate at t=1 second. Answer in the form: a(t)=Ct^3+Dt^−3−t^−2. C= D= a(1)=

The distance s(t), in meters, is given as a function of time, in seconds, below. s(t)=t^5−2/t+ln(9t) Find the velocity function and evaluate at t=2 seconds. Answer in the form: v(t)=At^4+2t^B+t^−1. A= B= v(2)= Find the acceleration function and evaluate at t=1 second. Answer in the form: a(t)=Ct^3+Dt^−3−t^−2. C= D= a(1)=

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 10P: An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in...

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Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

The distance s(t), in meters, is given as a function of time, in seconds, below.

s(t)=t^5−2/t+ln(9t)

Find the velocity function and evaluate at t=2 seconds.

Answer in the form: v(t)=At^4+2t^B+t^−1.

v(2)=

Find the acceleration function and evaluate at t=1 second.

Answer in the form: a(t)=Ct^3+Dt^−3−t^−2.

a(1)=

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