The distribution coefficient, k = concentration in hexanes concentration in water, between hexanes and water for solute A is 6.0. What weight of A would be removed by hexanes from a solution of 10 grams of A in 100 mL of water by a single extraction with 100 mL of hexanes? a.) What weight of A would be removed by two successive extractions with 50 mL of hexanes? b.)How many mL of hexanes would be required to remove 98% of A from a solution of 10 grams of A in 100 mL of water?

The distribution coefficient, k = concentration in hexanes concentration in water, between hexanes and water for solute A is 6.0. What weight of A would be removed by hexanes from a solution of 10 grams of A in 100 mL of water by a single extraction with 100 mL of hexanes? a.) What weight of A would be removed by two successive extractions with 50 mL of hexanes? b.)How many mL of hexanes would be required to remove 98% of A from a solution of 10 grams of A in 100 mL of water?

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter81: Extractions, Separations, And Drying Agents

Section: Chapter Questions

Problem 1P

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The distribution coefficient, k = concentration in hexanes concentration in water, between hexanes and water for solute A is 6.0. What weight of A would be removed by hexanes from a solution of 10 grams of A in 100 mL of water by a single extraction with 100 mL of hexanes? what weight of A would be removed by two successive extractions with 50 mL of hexanes? How many mL of hexanes would be required to remove 98% of A from a solution of 10 grams of A in 100 mL of water?
The distribution coefficient, k for a compound “A” between hexane and water is 7.5. What weight of A would be removed from a solution of 10 g of A in 100 mL of water by a single 100 mL extraction with hexane?
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