The Downitawn Parking Authority of Tampa, Florida, reported the following information for a sample of 234 customers on the numberof hours cars are parked and the amount they are charged.Number of Hours FrequencyAmountCharged$ 412523851456812143206141771936822234PaureClick here for the ExcelData Filea-1. Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 declmel places.)ProbabilityHours137Next5 of 10Prevpe here to search a-2 Is this a discrete or a continuous probability distribution?O DiscreteO Continuousb-1. Find the mean and the standard deviation of the number of hours parked. (Do not round the Intermediate calculations. Roundyour final answers to 3 declmal places.)MeanStandarddeviationb-2. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal(sappidhoursఎం; pax.ed s +2aO;2n2 (eaidh ఇq lc. Find the mean and the standard deviation of the amount chargec. (Do not round the Intermediate calculetions. Round your finelNextof 10KPrev

Question
Asked Oct 14, 2019
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The Downitawn Parking Authority of Tampa, Florida, reported the following information for a sample of 234 customers on the number
of hours cars are parked and the amount they are charged.
Number of Hours Frequency
Amount
Charged
$ 4
1
25
2
38
51
45
6
8
12
14
3
20
6
14
17
7
19
36
8
22
234
Paure
Click here for the Excel
Data File
a-1. Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 declmel places.)
Probability
Hours
1
3
7
Next
5 of 10
Prev
pe here to search
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The Downitawn Parking Authority of Tampa, Florida, reported the following information for a sample of 234 customers on the number of hours cars are parked and the amount they are charged. Number of Hours Frequency Amount Charged $ 4 1 25 2 38 51 45 6 8 12 14 3 20 6 14 17 7 19 36 8 22 234 Paure Click here for the Excel Data File a-1. Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 declmel places.) Probability Hours 1 3 7 Next 5 of 10 Prev pe here to search

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a-2 Is this a discrete or a continuous probability distribution?
O Discrete
O Continuous
b-1. Find the mean and the standard deviation of the number of hours parked. (Do not round the Intermediate calculations. Round
your final answers to 3 declmal places.)
Mean
Standard
deviation
b-2. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal
(sappid
hours
ఎం; pax.ed s +2aO;2n2 (eaidh ఇq l
c. Find the mean and the standard deviation of the amount chargec. (Do not round the Intermediate calculetions. Round your finel
Next
of 10
KPrev
help_outline

Image Transcriptionclose

a-2 Is this a discrete or a continuous probability distribution? O Discrete O Continuous b-1. Find the mean and the standard deviation of the number of hours parked. (Do not round the Intermediate calculations. Round your final answers to 3 declmal places.) Mean Standard deviation b-2. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal (sappid hours ఎం; pax.ed s +2aO;2n2 (eaidh ఇq l c. Find the mean and the standard deviation of the amount chargec. (Do not round the Intermediate calculetions. Round your finel Next of 10 KPrev

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Expert Answer

Step 1

Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If you want remaining sub-parts to be solved, then please resubmit the whole question and specify those sub-parts you want us to solve.

a1)

Probability distribution from the given distribution, can be calculated as:

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f p(x) Р(x)- Σf Hours (x) Frequency (fAmount 25 -=0.1068 4 234 1 25 38 -=0.1623 234 2 38 51 -=0.2179 234 3 51 8 45 -=0.1923 234 20 --0.0854 234 14 -=0.0598 234 45 12 4 14 17 6 14 5 --0.0213 234 7 5 19 36 -=0.1538 234 8 36 22 Σ1-234 Σp(t)-1 20

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Step 2

a2)

The number of hours is in integer. Thus, this is the discrete probability distribution.

Step 3

b1)

The mean and standard deviation of the number...

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хp(х) x*Р(x) 0.106838 0.106838 0.324786 0.649573 0.653846 1.961538 0.769231 3.076923 0.42735 2.136752 0.358974 2.153846 0.149573 1.047009 1.230769 9.846154 Mxp(x) 20.9786 Exp(r) 4.0213

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