The drawing shows a rectangular block of glass (ng = 1.49) surrounded by a liquid (n = 1.65). A ray of light is incident on the glass at point A with an angle of incidence, 0. If the angle of refraction at point B is 52°, then what is the angle of incidence at point A? Helpful Equations: n,Sinon,Sin0₂ || Sino = 1₂ (for:n, >n₂) || sin² 0+ cos² 0=1 || Sin(90° - 0) = cos 0 || n₁

Physics for Scientists and Engineers
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Author:Raymond A. Serway, John W. Jewett
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Chapter35: Image Fonnation
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The drawing shows a rectangular block of glass (ng = 1.49) surrounded by a liquid (n₁ = 1.65). A ray of light is
incident on the glass at point A with an angle of incidence, 0. If the angle of refraction at point B is 52°, then what
is the angle of incidence at point A?
Helpful Equations: n, Sin=n₂Sin0₂ || Sino
=
¹2 (for:n, >n₂) || sin² 0 + cos² 0=1 || Sin(90° - 0) = cos ||
n₁
B
Transcribed Image Text:The drawing shows a rectangular block of glass (ng = 1.49) surrounded by a liquid (n₁ = 1.65). A ray of light is incident on the glass at point A with an angle of incidence, 0. If the angle of refraction at point B is 52°, then what is the angle of incidence at point A? Helpful Equations: n, Sin=n₂Sin0₂ || Sino = ¹2 (for:n, >n₂) || sin² 0 + cos² 0=1 || Sin(90° - 0) = cos || n₁ B
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