The drawing shows two cars traveling in different directions with different speeds. Their velocities are: VAG = velocity of car A relative to the Ground = 27.3 m/s, due east VBG = velocity of car B relative to the Ground = 21.0 m/s, due north The driver of car B looks out the window and sees car A. What is the velocity (magnitude and direction) of car A as observed by the driver of car B? In other words, what is the velocity VAB of car A relative to car B? North Car A VAG VBG Car B East

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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Problem 3P: A particle initially located at the origin has an acceleration of a=3.00jm/s2 and an initial...
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The drawing shows two cars traveling in different directions with different speeds. Their velocities are:
VAG = velocity of car A relative to the Ground = 27.3 m/s, due east
VBG = velocity of car B relative to the Ground = 21.0 m/s, due north
The driver of car B looks out the window and sees car A. What is the velocity (magnitude and direction) of car A as observed by the
driver of car B? In other words, what is the velocity VAB of car A relative to car B?
North
Car A
VAG
VBG
Car B
East
Transcribed Image Text:The drawing shows two cars traveling in different directions with different speeds. Their velocities are: VAG = velocity of car A relative to the Ground = 27.3 m/s, due east VBG = velocity of car B relative to the Ground = 21.0 m/s, due north The driver of car B looks out the window and sees car A. What is the velocity (magnitude and direction) of car A as observed by the driver of car B? In other words, what is the velocity VAB of car A relative to car B? North Car A VAG VBG Car B East
Expert Solution
Step 1

The vector form of velocities of Car A and Car B is,

VAG=(27.3 m/s)i^

VBG=(21 m/s)j^

 

The velocity of car A as observed by the car B is,

VAB=VAG-VBG        =(27.3 m/s)i^-(21 m/s)j^

 

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