The electric field of an electromagnetic wave propagating through a vacuum Is given by: E = 250 sin (2nx101²t – n × 10*z) î en V/m. a. The direction of wave propagation b. Wavelength c. The expression of the corresponding magnetic field

The electric field of an electromagnetic wave propagating through a vacuum Is given by: E = 250 sin (2nx101²t – n × 10*z) î en V/m. a. The direction of wave propagation b. Wavelength c. The expression of the corresponding magnetic field

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter16: Electromagnetic Waves

Section: Chapter Questions

Problem 58P: The magnetic field of a plane electromagnetic wave moving along the z axis is given by B...

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Question

the question image is below

The electric field of an electromagnetic
wave propagating through a
vacuum
Is given by:
2
E = 250 sin (2nx1012t – n × 10*z)î en V/m.
The direction of wave propagation
b. Wavelength
c. The expression of the corresponding
magnetic field
d. The intensity of the radiation it
carries
e. The energy in eV that it transports
through a square surface of 40 cm sideways
for half an hour.

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