The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V. Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction. What is the magnitude of the electric field, in volts per meter, at x = 1.0 m? What is the direction of the electric field at x = 1.0 m? What is the magnitude of the electric field, in volts per meter, at x = 5.0 m? What is the direction of the electric field at x = 5.0 m?
The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V. Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction. What is the magnitude of the electric field, in volts per meter, at x = 1.0 m? What is the direction of the electric field at x = 1.0 m? What is the magnitude of the electric field, in volts per meter, at x = 5.0 m? What is the direction of the electric field at x = 5.0 m?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter26: Electric Potential
Section: Chapter Questions
Problem 55PQ: The electric potential is given by V = 4x2z + 2xy2 8yz2 in a region of space, with x, y, and z in...
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The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V.
Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction.
What is the magnitude of the electric field, in volts per meter, at x = 1.0 m?
What is the direction of the electric field at x = 1.0 m?
What is the magnitude of the electric field, in volts per meter, at x = 5.0 m?
What is the direction of the electric field at x = 5.0 m?
Expert Solution
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The electric field strength is the negative of the potential gradient.
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