The electrode potential for the following two half reactions are as follows: Al+3 + 3 e- = Al(s) E = (-)1.66 V Fe+2 + 2e- = Fe(s) E = (-) 0.44 V. An electrochemical cell has an Al anode immersed in aluminum sulfate solution and a Fe cathode immersed in an iron (II) sulfate solution. The voltage generated by this cell would be: a) -2.10 V b) + 2.10 V c) -1.22 V d) + 1.22 VThe number of electrons transferred in the reaction A) 2 b) 3 C0 5 d) 6

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Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 80E: An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] =...

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The electrode potential for the following two half reactions are as follows: Al+3 + 3 e- = Al(s) E = (-)1.66 V Fe+2 + 2e- = Fe(s) E = (-) 0.44 V. An electrochemical cell has an Al anode immersed in aluminum sulfate solution and a Fe cathode immersed in an iron (II) sulfate solution. The voltage generated by this cell would be: a) -2.10 V b) + 2.10 V c) -1.22 V d) + 1.22 V

The number of electrons transferred in the reaction A) 2 b) 3 C0 5 d) 6

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