The end of a tuning fork moves in simple harmonic motion described by the equation d = a sin (ot). If a tuning fork for the note D above middle C on an even-tempered scale has a frequency of 293.66 hertz (cycles per second), find. If the maximum displacement of the end of the tuning fork is 0.01 millimeter, determine the equation that describes the movement of the tuning fork. (Simplify your answer. Type an exact answer, using as needed.) Choose the equation that describes the movement of the tuning fork. Od=0.005 sin (587.32xt) O d = 0.005 sin (293.66mt) Od 0.01 sin (587.32xt) O d=0.005 sin 293.66 O Od 0.01 sin (293.66xt) d=0.01 sin 293.66

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
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Chapter17: Traveling Waves
Section: Chapter Questions
Problem 14PQ
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The end of a tuning fork moves in simple harmonic motion described by the equation d = a sin (ot). If a tuning fork for the note D above middle C on an even-tempered scale has a frequency of 293.66 hertz (cycles per second), find w. If the maximum displacement of
the end of the tuning fork is 0.01 millimeter, determine the equation that describes the movement of the tuning fork.
@=
(Simplify your answer. Type an exact answer, using as needed.)
Choose the equation that describes the movement of the tuning fork.
d = 0.005 sin (587.32nt)
d = 0.005 sin (293.66лt)
d = 0.01 sin (587.32лt)
π
d = 0.005 sin
293.66
d = 0.01 sin (293.66лt)
π
d = 0.01 sin
293.66
Transcribed Image Text:The end of a tuning fork moves in simple harmonic motion described by the equation d = a sin (ot). If a tuning fork for the note D above middle C on an even-tempered scale has a frequency of 293.66 hertz (cycles per second), find w. If the maximum displacement of the end of the tuning fork is 0.01 millimeter, determine the equation that describes the movement of the tuning fork. @= (Simplify your answer. Type an exact answer, using as needed.) Choose the equation that describes the movement of the tuning fork. d = 0.005 sin (587.32nt) d = 0.005 sin (293.66лt) d = 0.01 sin (587.32лt) π d = 0.005 sin 293.66 d = 0.01 sin (293.66лt) π d = 0.01 sin 293.66
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