Question
Asked Nov 24, 2019
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The energy for one state of He ion is -3.49 x 10-19 J. What frequency of light would need to be
emitted to reach a state with an energy of -9.69 x 10-19 J?
A.
1.32 x 10-18 Hz
В.
2.22x 1016 Hz
6.20x 10-18 Hz
С.
D.
9.35 x 1014 Hz
Е.
1.99 x 1015 Hz
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The energy for one state of He ion is -3.49 x 10-19 J. What frequency of light would need to be emitted to reach a state with an energy of -9.69 x 10-19 J? A. 1.32 x 10-18 Hz В. 2.22x 1016 Hz 6.20x 10-18 Hz С. D. 9.35 x 1014 Hz Е. 1.99 x 1015 Hz

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Expert Answer

Step 1

It is given that:

Initial energy (E1) = -9.69×10-19 J

Final energy (E2) = -3.49×10-19 J

Step 2

The energy change can be expressed as the product of a constant that is plank’s constant(h) and frequency(ν). The mathematical expression for this is given as:

AE hv
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AE hv

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Step 3

Plugging the value of initial and final energy and Planck’s constant ...

AE = hv
(E-E) hv
(E,-E
h
-3.49x1019(9.69 x 10-9) J
6.626x1034 J.S
-3.49x109+(9.69x 10-)J
6.626x10 J.S
6.2x 1019
6.626x103 s
0.935x1015 Hz
=9.35x10 Hz
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AE = hv (E-E) hv (E,-E h -3.49x1019(9.69 x 10-9) J 6.626x1034 J.S -3.49x109+(9.69x 10-)J 6.626x10 J.S 6.2x 1019 6.626x103 s 0.935x1015 Hz =9.35x10 Hz

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