The equilibrium constant for the following reaction is 3.13x103 at 32 °C. N2(g) + 02(g) = 2 NO(g) K = 3.13x103 at 32 °C Calculate the equilibrium constant for the following reactions at 32 °C. (a) 2 NO(g) N2(g) + O2(g) K = (b) NO(g)=1/2 N2(g) + 1/2 02(g) K =

Chemistry & Chemical Reactivity
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Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
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The equilibrium constant for the following reaction is 3.13x103 at 32 °C.
N2(g) + O2(g) =2 NO(g)
= 3.13×103 at 32 °C
Calculate the equilibrium constant for the following reactions at 32 °C.
(a) 2 NO(g) = N2(g) + 02(g)
K =
(b) NO(g)=1/2 N2(g) + 1/2 02(g)
K =
Transcribed Image Text:The equilibrium constant for the following reaction is 3.13x103 at 32 °C. N2(g) + O2(g) =2 NO(g) = 3.13×103 at 32 °C Calculate the equilibrium constant for the following reactions at 32 °C. (a) 2 NO(g) = N2(g) + 02(g) K = (b) NO(g)=1/2 N2(g) + 1/2 02(g) K =
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