The equilibrium constant, K, for the following reaction is 2.36x10-2 at 618 K. COCI₂(g) =CO(g) + Cl₂(9) An equilibrium mixture of the three gases in a 7.82 L container at 618 K contains 0.301 M COCl₂, 8.42×10-2 M CO and 8.42×10-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 15.7 L? [COCI₂] = [Co] = [Cl₂] M M M

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