The equilibrium for the reaction between (CH3)2NH(CH3)2NH, a weak base, and water is represented by the equation below. The table shows the pHpH of three solutions of (CH3)2NH(aq)(CH3)2NH(aq) at 25°C25°C. (CH3)2NH(aq)+H2O(l)⇄(CH3)2NH2+(aq)+OH-(aq)Kb=5.4×10−4at25°C(CH3)2NH(aq)+H2O(l)⇄(CH3)2NH2+(aq)+OH−(aq)Kb=5.4×10−4at25°C [(CH3)2NH][(CH3)2NH] pH at25°CpH at25°C 0.050 11.69 0.10 11.85 0.20 12.01   Based on the information given, which of the following is true?     a.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pOHpOH because to reach equilibrium a smaller amount of the conjugate acid (CH3)2NH2+(CH3)2NH2+ is produced.   b.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pOHpOH because to reach equilibrium more OH−OH− is produced.   c.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pHpH because to reach equilibrium a smaller amount of the conjugate acid (CH3)2NH2+(CH3)2NH2+ is produced.   d.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pHpH because to reach equilibrium more OH−OH− is produced.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter16: Spontaneity Of Reaction
Section: Chapter Questions
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The equilibrium for the reaction between (CH3)2NH(CH3)2NH, a weak base, and water is represented by the equation below. The table shows the pHpH of three solutions of (CH3)2NH(aq)(CH3)2NH(aq) at 25°C25°C.

(CH3)2NH(aq)+H2O(l)⇄(CH3)2NH2+(aq)+OH-(aq)Kb=5.4×10−4at25°C(CH3)2NH(aq)+H2O(l)⇄(CH3)2NH2+(aq)+OH−(aq)Kb=5.4×10−4at25°C

[(CH3)2NH][(CH3)2NH] pH at25°CpH at25°C
0.050 11.69
0.10 11.85
0.20 12.01
 

Based on the information given, which of the following is true?

 
 

a.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pOHpOH because to reach equilibrium a smaller amount of the conjugate acid (CH3)2NH2+(CH3)2NH2+ is produced.

 

b.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pOHpOH because to reach equilibrium more OH−OH− is produced.

 

c.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pHpH because to reach equilibrium a smaller amount of the conjugate acid (CH3)2NH2+(CH3)2NH2+ is produced.

 

d.Solutions with a higher concentration of (CH3)2NH(CH3)2NH have a higher pHpH because to reach equilibrium more OH−OH− is produced.

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