4 ProblemConsider an aluminum rod of length L = 2 m and cross-sectional area A = 0.01 m² (shown on theleft). Attached to the rod tip is a concentrated mass mc = 10 kg, and a force u(t) is applied whichcauses a small amount of extension/compression of the rod. An equivalent lumped parameter mdkLMcu(t)meJu(t)model of the system is shown on the right. Assume that the density of aluminum is pkg/m³ and Young's modulus is E 68 x 10 Pa.Using the lumped parameter tables from Lecture 15 to find:⚫ the equivalent lumped mass me⚫ the equivalent stiffness kusing the above expressions determine the transfer function G(s) = X(s)/U(s).=== 2710

The equivalent lumped mass of the system can be found using the formula:me=mc+ρALwhere ρ is the…

Answered: The transfer function G(s) = X(s)/U(s).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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