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The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoffs Law gives RI + = E(t). OP dt Since the current is I we have = 0- C = E(t). dt Suppose the resistance is 30 2, the capacitance is 0.2F, a battery gives a constant voltage of E(t) = 60V, and the initial charge is Q(0) = 0C.

The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoffs Law gives RI + = E(t). OP dt Since the current is I we have = 0- C = E(t). dt Suppose the resistance is 30 2, the capacitance is 0.2F, a battery gives a constant voltage of E(t) = 60V, and the initial charge is Q(0) = 0C.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 46E
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Find the charge and the current at time t correctly.

Q(t)=______________________

I(t)=______________________

The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + 2 = E(t). OP we have dt Since the current is I = 1 GO = E(t). dt Suppose the resistance is 30 2, the capacitance is 0.2F, a battery gives a constant voltage of E(t) = 60V, and the initial charge is Q(0) = 0C.
Transcribed Image Text:The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + 2 = E(t). OP we have dt Since the current is I = 1 GO = E(t). dt Suppose the resistance is 30 2, the capacitance is 0.2F, a battery gives a constant voltage of E(t) = 60V, and the initial charge is Q(0) = 0C.
E R switch
Transcribed Image Text:E R switch
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