The figure below is a scaled representation of a planet's orbit with a semimajor axis of 1.598 AU. (Use the exact values you enter in previous answer(s) to make later calculation(s).) (a) Find the ratio of the aphelion-to-perihelion distance. TA (b) Find the perihelion and aphelion distances in astronomical units. AU TA = AU

The figure below is a scaled representation of a planet's orbit with a semimajor axis of 1.598 AU. (Use the exact values you enter in previous answer(s) to make later calculation(s).) (a) Find the ratio of the aphelion-to-perihelion distance. TA (b) Find the perihelion and aphelion distances in astronomical units. AU TA = AU

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter7: Gravity

Section: Chapter Questions

Problem 9PQ

See similar textbooks

Similar questions

If the semi-major axis, a, is measured in AU and the orbital period, p, is measured in years, then Kepler's 3rd law allows us to calculate the mass of the object they are orbiting using the following equation: M = a3/p2 Furthermore, the mass that is calculated by this equation is given in solar masses (MSun) where, by definition, the Sun's mass is 1 MSun. Now, suppose I were to tell you that the mass of Jupiter is equal to 4.5e7 MSun. Does the stated mass of Jupiter make sense? it is to big or to small or makes sense
Asteroid X in the Solar System has a semimajor axis of 3.25 AU and an orbital period that is 125 days shorter than that of asteroid Y. What is the semimajor axis of asteroid Y, in AU?
calculate the periof T of a planet whose orbit has semimajor axis of 10AU
Let's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Mercury. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth years
Let's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Answer for the highlighted planet in each question. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Earth. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth years
Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)
Suppose, hypothetically, that the Earth orbited the Sun at half its current distance. (That is, at 1/2 AU instead of 1 AU). What would be the length of the year? What else would be different?
The table below lists the average distance R to the Sun and orbital period T of the first planets:Distance Orbital PeriodMercury 0.39 AU 88 daysVenus 0.72 AU 225 daysEarth 1.00 AU 365 daysMars 1.52 AU 687 days(a) Calculate the average distance of Mercury, Venus and Mars to the Earth.Which one of these planets is the closest to Earth on average?(b) Calculate the average distance of Mercury, Venus and Earth to Mars.Which one of these planets is the closest to Mars on average?(c) What do you expect for the other planets?Hint: Assume circular orbits and use symmetries to make the distance calculation easier. You canapproximate the average distance by using four well-chosen points on the planet’s orbit.
What would be the period of revolution of a hypothetical planet whose circular orbit around the sun has a radius of 1.75 AU? (Hint: 1 AU = 1 Astronomical Unit = 1.5*1011) a) 2.3 yrs b) 1.45 yrs c) 2.9 yrs
From the data measured read off the period, P and the orbital radius, a from thegraph for the moon Ganymede . These values will have units of hours for the period P, and Jupiter Diameters (J.D.) for a. Enter your results here:P (period) = _________ hours a (orbital radius) = ________ J.D. After,In order to use Kepler's Third Law, you need to convert the period into years, using: 1 day = 24 hours and 1 year = 365.25 days. The orbital radius must be converted to A.U., using 1050 J.D. = 1 A.U. Enter your converted values here: P (period) = _________ years a (orbital radius) = ________ A.U.
A projectile is fired straight upward from planet's surface with a speed that is 1/7 the planet's escape speed. Let R be the radius of the planet. What is the highest distance from the center of the planet in units of R the projectile will reach? Give your answer to three significant figures.
Kepler’s third law says that the orbital period (in years) is proportional to the square root of the cube of the mean distance (in AU) from the Sun (Pa1.5) . For mean distances from 0.1 to 32 AU, calculate and plot a curve showing the expected Keplerian period. For each planet in our solar system, look up the mean distance from the Sun in AU and the orbital period in years and overplot these data on the theoretical Keplerian curve.