The figure below represents the top view of a cubic gaussian surface in a uniform electric field E oriented parallel to the top and bottom faces of the cube. The field makes an angle 0 with side 0, and the area of each face is A. (Use any variable or symbolstated above along with the following as necessary: E for the magnitude of the electric field.)3(a) In symbolic form, find the electric flux through face 0.(b) In symbolic form, find the electric flux through in ®.PE =(c) In symbolic form, find the electric flux through face ®.(d) In symbolic form, find the electric flux through face 0.(e) In symbolic form, find the electric flux through the top and bottom faces of the cube.(*.).topbottom(f) What is the net electric flux through the cube?PE =(g) How much charge is enclosed within the gaussian surface?qin =Submit Answer

It is given a top view of the cubic Gaussian surface in a uniform electric field E→ oriented…

The figure below represents the top view of a cubic gaussian surface in a uniform electric field E oriented parallel to the top and bottom faces of the cube. The field makes an angle 8 with side 0, and the area of each face is A. (Use any variable or symbol stated above along with the following as necessary: E for the magnitude of the electric field.) 2

The figure below represents the top view of a cubic gaussian surface in a uniform electric field E oriented parallel to the top and bottom faces of the cube. The field makes an angle 8 with side 0, and the area of each face is A. (Use any variable or symbol stated above along with the following as necessary: E for the magnitude of the electric field.) 2

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 12PQ

See similar textbooks

Similar questions

A cylinder of diameter 1.72 m is in a region where the electric field is as shown in the figure below. If E1 = 42.4 N/C and E2 = 23.1 N/C, what is the net flux through the two end faces of the cylinder? Note that the diagram is not to scale.
A uniform electric field of magnitude E = 460 N/C makes an angle of ? = 65.5° with a plane surface of area A = 3.60 m2 as in the figure below. Find the electric flux through this surface. A side view is shown of a plane surface, where one of its dimensions is into the page and the other is horizontal. A uniform electric field, vector E, is incident on the surface. Vector E points down and left, making an acute angle ? with the surface. N · m2/C
A disk of radius 0.10 m is oriented with its normal vector n at 30 degrees to a unform electric field E vector of a magnitude of 2.0x10^3 N/C. What is the electric flux through the disk? (Provide the complete details for the Illustrated Diagram - inside the box, Given, Required, Equation, Solution, and Answer)
A uniform electric field measured over a square surface with side length d = 15.5 cm makes an angle θ = 67.0° with a line normal to that surface, as shown in the figure below. There is a square horizontal surface with length and width d. The surface has a normal vertical axis at the center with a vector labeled vector E traveling from the center of the plane up and to the right. Vector E and the normal vertical axis form an angle labeled θ. If the net flux through the square is 5.40 N · m2/C, what is the magnitude Eof the electric field (in N/C)? N/C
A cylinder of diameter 1.72 m is in a region where the electric field is as shown in the figure below. If E1 = 38.0 N/C and E2 = 20.1 N/C, what is the net flux through the two end faces of the cylinder? Note that the diagram is not to scale. N · m2/C
Consider a plane surface in a uniform electric field as in the Figure , where cm and . If the net flux through the surface is 6.00 Nm2/C, find the magnitude of the electric field.
Consider a plane surface in a uniform electric field as shown in the figure, where d =20 cm and the angle= 70. The net flux through the surface is 7 N.m2/C. What is the magnitude of the electric field? In N/C.
Find the net electric flux (N · m2/C) through the spherical closed surface shown in the figure below. The two charges on the right are inside the spherical surface. Take q1 = +1.96 nC, q2 = +1.04 nC, and q3 = -3.24 nC.)
The cube in the figure has edge length 1.87 m and is oriented as shown in a region of uniform electric field. Find the electric flux through the right face if the electric field (a) is in the positive x direction and has magnitude 8.81 N/C, (b) is in the negative y direction and has magnitude 2.22 N/C, and (c) is in the xz plane, has x component -2.75 N/C, and has z component 4.53 N/C. (d) What is the total flux through the cube's surface for each field?
A square surface with sides of 2 m × 2m is located over the xy-plane, where a constant electric field with a magnitude of 150 Nm^2/C^2 is present. The direction of the electric field vector is parallel with the surface. What is the total electric flux present in the surface? Please show me a detailed, complete solution. Thank you very much!
A solid insulating plastic sphere of radius a carries atotal net positive charge 3Q uniformly distributed throughout its interior.The insulating sphere is coated with a metallic layer of inner radius a andouter radius 2a. The conducting metallic layer carries a net charge of -2Q. Apply Gauss’s law to find the magnitude of the electric field in the region r < a. Inthe figure, draw the Gaussian surface you are using, and indicate on that surface the direction of anyvectors which appear in the mathematical expression of Gauss’s law. Express your answer in terms ofa, Q, r, and ε0. (If you get an expression involving ρ, substitute it from above to re-express youranswer in terms of the stated variables.)
Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: The flux through surface 1 is: . The flux through surface 2 is: . The flux through surface 3 is: . The flux through the surface on the xy plane is: . The flux through the surface on the xz plane is: . The flux through the surface on the yz plane is: . Taking the algebraic sum, the net electric flux through the cube is: .