The figure below shows three edge views of a square loop with sides of length = 0.425 m in a magnetic field of magnitude 1.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. HINT B (b) 60.0° from the magnetic field Wb (a) perpendicular to the magnetic field Wb (c) parallel to the magnetic field Wb 60.0° x The magnetic flux is B = BA cos(0) where is the angle between the magnetic field and the loop normal. y Click the hint button again to remove this hint. x
The figure below shows three edge views of a square loop with sides of length = 0.425 m in a magnetic field of magnitude 1.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field. HINT B (b) 60.0° from the magnetic field Wb (a) perpendicular to the magnetic field Wb (c) parallel to the magnetic field Wb 60.0° x The magnetic flux is B = BA cos(0) where is the angle between the magnetic field and the loop normal. y Click the hint button again to remove this hint. x
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter32: Faraday’s Law Of Induction
Section: Chapter Questions
Problem 65PQ
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