The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fig. I Fg.2 a) Calculate the capacitance of this capacitor. b) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface?

Physics for Scientists and Engineers with Modern Physics
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Author:Raymond A. Serway, John W. Jewett
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Chapter30: Faraday's Law
Section: Chapter Questions
Problem 50CP
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Use the following constants if necessary. Coulomb constant, k=8.987×109N-m2/C2.
Vacuum permitivity, eo=8.854×10-12F/m. Magnetic Permeability of
vacuum, µo=12.566370614356×10-7H/m. Magnitude of the Charge of one
electron, e=-1.60217662×10-19C. Mass of one electron, me=9.10938356×10-31kg.
Unless specified otherwise, each symbol carries their usual meaning. For
example, µC means microcoulomb.
The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core
with radius ri=3mm and outer hollow conducting tube with an inner radius
of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional
view of the system. This system of rod and shell is connected to a voltage source of
emf E=6.4volts. There is no dielectric material present in the system as of now.
Fig. I
Fig.2
a) Calculate the capacitance of this capacitor.
b) Say the inner rod is positively charged. Given this, calculate the charge density of the
outer surface. And show how the electric field lines are oriented in this system. Hint: you
can use the cross section for this (Fig. 2).
What is charge density of the outer surface?
Transcribed Image Text:Use the following constants if necessary. Coulomb constant, k=8.987×109N-m2/C2. Vacuum permitivity, eo=8.854×10-12F/m. Magnetic Permeability of vacuum, µo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662×10-19C. Mass of one electron, me=9.10938356×10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fig. I Fig.2 a) Calculate the capacitance of this capacitor. b) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). What is charge density of the outer surface?
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