The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at 0, = 25.0°. ForceF2 has a magnitude of 7.00 N and is at 6, = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0i – 12.0j) m/s, and (c) has theV = (14.0ti – 14.0fj) m/s², where t is time?-

Name: The figure shows an overhead view of a 0.0260 kg lemon half and two o
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at 0, = 25.0°. ForceF2 has a magnitude of 7.00 N and is at

At equilibirium net force is zero F→net=0 or F1→+F2→+F3→=0 Given F1=6.00 N at θ1=25.0°F2=7.00 N at…

Science

Physics

The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at 6, = 25.0°. Force F2 has a magnitude of 7.00 N and is at 6, = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0 – 12.0) m/s, and (c) has the V = (14.0fi – 14.0fj) m/s², wheret is time?

The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at 6, = 25.0°. Force F2 has a magnitude of 7.00 N and is at 6, = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0 – 12.0) m/s, and (c) has the V = (14.0fi – 14.0fj) m/s², wheret is time?

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 15P: The helicopter view in Fig. P3.15 shows two people pulling on a stubborn mule. The person on the...

See similar textbooks

Similar questions

The helicopter view in Fig. P3.15 shows two people pulling on a stubborn mule. The person on the right pulls with a force F1 of magnitude 120 X and direction of 1 = 60.0. The person on the left pulls with a force F2 of magnitude 80.0 N and direction of 2 = 75.0. Find (a) the single force that is equivalent to the two forces shown and (b) the force that a third person would have to exert on the mule to make the resultant force equal to zero. The forces are measured in units of newtons (symbolized N). Figure P3.15
A force F1 of magnitude 6.00 units acts on an object at the origin in a direction = 30.0 above the positive x axis (Fig. P3.7). A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y axis. Find graphically the magnitude and direction of the resultant force F1+F2. Figure P3.7
A 3.00-kg object is moving in a plane, with its x and y coordinates given by x = 5t2 1 and y = 3t3 + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.00 s.
The figure shows an overhead view of a 0.025 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3 N and is at θ1 = 29˚. Force F→2 has a magnitude of 8 N and is at θ2 = 27˚. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→=(11î −16ĵ ) m/s, and (c) has the v→=(11tî −11tĵ ) m/s2, where t is time?
A particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude 18N and is directed to the left and down, making an angle of 40 degrees with the vertical. The force G has magnitude 15N and is directed to the right and down, making an angle of 70 degrees with the horizontal. Find the magnitude of the vector H and the acute angle it makes with the horizontal.
In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
There are two forces on the 1.19 kg box in the overhead view of the figure but only one is shown. For F1 = 15.7 N, a = 14.7 m/s2, and θ = 34.1°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
As shown in the attached figure below, three force vectors act on an object. The magnitudes of the forces are F1= 80.0 N, F2 = 60.0 N, and F3 = 40.0 N, where N is the standard SI unit of force. The resultant force acting on the object is given by A. 40.0 N at an angle 60.0° below +x-axis B. 60.0 N at an angle 90.0° above +x-axis C. 20.0 N at an angle 34.3° below +x-axis D. 180 N at an angle 60.0° below +x-axis E. 35.5 N at an angle 34.3° above +x-axis
A particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude 16N and is directed to the right and down, making an angle of 50 degrees with the horizontal. The force G has magnitude 7N and is directed to the left and down, making an angle of 50 degrees with the horizontal. Find the magnitude of the vector H, and the acute angle it makes with the horizontal. Give the magnitude to one decimal place and the angle to the nearest degree. What is the magnitude of H and what is the acute angle H makes with the horizon?
If a force is applied with a magnitude of 200 N at 30 degrees above the horizontal, what are the horizontal and vertical components of this force? Group of answer choices Fa,h= 136.667 N Fa,v= 87.334 N Fa,h= 200 N Fa,v= 200 N Fa,h= 173.2 N Fa,v= 100 N Fa,h= 150 n Fa,v= 50 N
An antelope is being pulled by two forces whose vector-component expressions are: F1 = 0.7Ni + 0.5Nj + 7.2Nk F2 = 9.9Ni + -9.2Nj + -8.1Nk What is the angle between these two vectors?
An antelope is being pulled by two forces whose vector-component expressions are: F1 = -2.2Ni + 1.5Nj + -8.9Nk F2 = 7.7Ni + -3.7Nj + 4.1Nk What is the angle (in degrees) between these two vectors?