The figure shows two charged particles on an x axis: -g = -1.60 x 10-19 C at x = -3.00 m and a = 1.60 x 1019 C at x = 3.00 m. What are the (a) x- and (b) y- components of the net electric field produced at point P at y = 7.00 m? X= 3,00 m 9= 7.00m 2= 1160 X10-19c O =tan- ) E, O=tan- Zoo 3.00 Use pythagortar theoren &ニ 66.80° %3D 19:00+49 Thus the x-components of 2,: El ectRic field dne to e = Eq and E-2 Will be Eg Coso and E-g Cos& -9 - 30om E2 = magnitude of electric fled due to t82 at point Pwill be? 3.00 m. (a) Number i 9,7e062772 E-12+ 9,7806267E 2 Units Ex= 1195612554 È " NIC

Principles of Physics: A Calculus-Based Text
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Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 52P: A cylindrical shell of radius 7.00 cm and length 2.40 m has its charge uniformly distributed on its...
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The figure shows two charged particles on an x axis: -g = -1.60 x 10-19 C at x = -3.00 m and g = 1.60 x 10-19 C at x = 3.00 m. What are
the (a) x- and (b) y- components of the net electric field produced at point P at y = 7.00 m?
(*)
X= 3,00 m
9ミ700m
Ĉ= 1160X10-19 C
O =tan-
E,
Use pythagorta, theoken
シ=ten-! Z
3.00
9i00+49
2,: El ectRic field olne to e =
o = 66.80°
Thus the x-components of
and E
Eq
be
-2
will
(2:00.0)
COSo ard E-2
Cos o
ー7
- 300m
E2= magnitude of electruc fled
due to +82 at point Pwill be8
3.00 m
it.
(a) Number
i
Units
9,78062772 E-12+ 9,7806267E 2,
Ex= 1195612554 È
NIC
(b) Number
i
Units
N/C
® Ey= Eq;
SIN O-
Egz SINO =0
1i44X16-9 - 2,43275862810 |! outuonds
58
O Piease explain wly my.
tiral ansurer fau Ex Ys z
incorrecti A
ニ
Similary
-2 -E2 = 2at48275862X16 Cinwande)
thank gou!
Transcribed Image Text:#2 The figure shows two charged particles on an x axis: -g = -1.60 x 10-19 C at x = -3.00 m and g = 1.60 x 10-19 C at x = 3.00 m. What are the (a) x- and (b) y- components of the net electric field produced at point P at y = 7.00 m? (*) X= 3,00 m 9ミ700m Ĉ= 1160X10-19 C O =tan- E, Use pythagorta, theoken シ=ten-! Z 3.00 9i00+49 2,: El ectRic field olne to e = o = 66.80° Thus the x-components of and E Eq be -2 will (2:00.0) COSo ard E-2 Cos o ー7 - 300m E2= magnitude of electruc fled due to +82 at point Pwill be8 3.00 m it. (a) Number i Units 9,78062772 E-12+ 9,7806267E 2, Ex= 1195612554 È NIC (b) Number i Units N/C ® Ey= Eq; SIN O- Egz SINO =0 1i44X16-9 - 2,43275862810 |! outuonds 58 O Piease explain wly my. tiral ansurer fau Ex Ys z incorrecti A ニ Similary -2 -E2 = 2at48275862X16 Cinwande) thank gou!
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