The first two bytes of a 4M x 16 main memory have the following hex values: Byte 0: FF Byte 1: 01 If these bytes hold a 16-bit two's complement integer, what is the actual decimal value if: a) memory is big endian:__________________ b) memory is little endian:__________________
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A: Given main memory : 1 M x 8 From given memory, total locations are 1M each location size = 8 bits
The first two bytes of a 4M x 16 main memory have the following hex values:
Byte 0: FF
Byte 1: 01
If these bytes hold a 16-bit two's complement integer, what is the actual decimal value if:
a) memory is big endian:__________________
b) memory is little endian:__________________
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- Assume a 2^20 byte memory (2^20 x 8):A. What are the lowest and highest addresses if memory is byte-addressable?B. What are the lowest and highest addresses if memory is word-addressable, assuming a16-bit word?C. What are the lowest and highest addresses if memory is word-addressable, assuming a32-bit word?8Gbx32 ROM element is given. a) Specify the address line and the data number line. b) How many bits is the total storage capacity of the memory? c) The total storage capacity of the memory can be specified in Megabytes.d) If we have two 4Gbx16 ROMs, two 2Gbx16 and 2Gbx32 modules, use these elements to design the 8Gbx32 bit memory unit as block diagrams. Express it in a descriptive way.The first two bytes of a 4M x 16 main memory have the following Hex values: Byte 0 is FE Byte 1 is 04 If these bytes hold a 16-bit two's complement integer, what is its actual decimal value if: a) Memory is big endian? b) Memory is little endian? 2. The memory unit of a computer has 2M Words of 32 bits (or 4 bytes) each. The computer has an instruction format with 4 fields: an opcode field; an addressing mode field to specify 1 of 6 addressing modes; a register address field to specify one of 7 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: How large must the addressing mode field be? How large must the register field be? How large must the address field be? How large is the opcode field?
- The first two bytes of a 2M × 16 main memory have the following hex values:1. Byte 0 is FE2. Byte 1 is 01If these bytes hold a 16-bit two’s complement integer, what is its actual decimal value if:1. a) Memory is big endian?2. b) Memory is little endian?The first two bytes of a 2M x 16 main memory have the following hex values:Byte 0 is FEByte 1 is 01If these bytes hold a 16-bit two's complement integer, what is its actual decimal value if:a. memory is big endian?b. memory is little endian?At a minimum, how many bits are needed in the MAR with each of the following memory sizes? a. 1 million bytes b. 10 million bytes c. 100 million bytes d. 1 billion bytes
- b. How many bits are required to address a 4M × 16 main memory if main memory is byte-addressable?c. How many bits are required to address a 1M × 8 main memory if main memory is byte-addressable?Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
- How many bits are required to address 4G Bytes main memory if a) Main memory is byte-addressable? b)Main memory is word-addressable? (word size is 32 bits or 4 Bytes) c)If the main memory will be built on 512M Bytes memory chips, how many RAM chips are needed?If the last address of the memory is 0xFFF, what is the size of the memory? A. 4K Byte B. 8K Byte C. 256 Byte D. 32760 bits E. 1K ByteConsider memory storage of a 32-bit word stored at memory word 34 in a byte addressable memory. (a) What is the byte address of memory word 34? (b) What are the byte addresses that memory word 34 spans? (c) Draw the number 0x3F526372 stored at word 342 in both big-endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.