The flux received at the Earth from Supernova 1885 was 3.0182 x 10 10 W/m?. The luminosity of the supernova is 6 x 10° Lo (or 6 x 10° solar luminosities). What is the distance to the supernova in parsecs? Take 1 pc = 3.0857 × 1016 m and Lo= 3.828 × 1026 w. d = pc

The flux received at the Earth from Supernova 1885 was 3.0182 x 10 10 W/m?. The luminosity of the supernova is 6 x 10° Lo (or 6 x 10° solar luminosities). What is the distance to the supernova in parsecs? Take 1 pc = 3.0857 × 1016 m and Lo= 3.828 × 1026 w. d = pc

Stars and Galaxies (MindTap Course List)

10th Edition

ISBN:9781337399944

Author:Michael A. Seeds

Publisher:Michael A. Seeds

Chapter16: Galaxies

Section: Chapter Questions

Problem 13RQ

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Concept explainers

Stellar evolution

We may see thousands of stars in the dark sky. Our universe consists of billions of stars. Stars may appear tiny to us but they are huge balls of gasses. Sun is a star of average size. Some stars are even a thousand times larger than the sun. The stars do not exist forever they have a certain lifetime. The life span of the sun is about 10 billion years. The star undergoes various changes during its lifetime, this process is called stellar evolution. The structure of the sun-like star is shown below.

Red Shift

It is an astronomical phenomenon. In this phenomenon, increase in wavelength with corresponding decrease in photon energy and frequency of radiation of light. It is the displacement of spectrum of any kind of astronomical object to the longer wavelengths (red) side.

Question

The flux received at the Earth from Supernova 1885 was 3.0182 x 10 10 W/m². The luminosity of
the supernova is 6 x 10° Lo (or 6 x 10° solar luminosities).
What is the distance to the supernova in parsecs? Take 1 pc = 3.0857 x 1016 m and Lo= 3.828 x
1026 w.
d =
pc

Expert Solution

Step 1

$f l u x (I) = 3.0182 \times 10^{- 10} \frac{W}{m^{2}} l u m i n o s i t y = 6 \times 10^{9} s o l a r l u m i n o s i t i e s$

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