Math 100(MMW)._Activity 06.docxMOREActivity 6.1.followinTheforfour colleges aretableshowsthemumbeTof ennolleeseachthefourcollegesinB niversity.TheArtsand Sciences (CASI. Business(CEng).Administration(BA). EngineeringandFineArts (C FAJ. There are 180 nerw projcctors that are to beapportioHed among the colleges based on the number ofenrollees.CollegeEnrol mantCAS34555780CEng1896CFA4678a What is the standard divisor for an apportionm entof the prajectors?Use the Hamilton method to determine the mumberof projectors to be apportioned to each college.e. IF the projectors areJefferson method, explain why neither 86can be used as a modiied standard divisor. Explainwhy B6.5divisor.b.to be apPPportioned using thenor 87besedmodified standardcand. Explain why the modified standard divisor usedin the Jefferson method cannot be larger tha thestandard divisor.e. Use the Jefferson method to determine the numberof projectors to be apportioned to each college.f. How do the apportionment results produced usingthe Jefferson method compare withproduced using the Hamilton method?the results2.The members of a scholarship committee have rankedfour finalists competing for a scholarship in order ofpreferencoe. The results are shown in the preferenceschedule below.CandidateRankingsA4B12341Numberof nateSIf you are one of the voting members and ynou wantcandidatetowin the scholarship, which votingmethod would you suggest that the committee use?

Name: Math 100(MMW)._Activity 06.docxMOREActivity 6.1.followinTheforfour co
Uploaded: 2024-03-05T11:53:49.000Z
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Description: Math 100(MMW)._Activity 06.docxMOREActivity 6.1.followinTheforfour colleges aretableshowsthemumbeTof ennolleeseachthefourcollegesinB niversity.TheArtsand Sciences (CASI. Business(CEng).Administration(BA). EngineeringandFineArts (C FAJ. There are 180