Do it on https://www.sim8085/ .. Code with output is needed The following block of data is stored in the memory locations from XX55H toXX5AH. Transfer the data to the locations XX80H to XX85H in the reverse order(e.g., the data byte 22H should be stored at XX85H and 37H at XX80H).Data(H)22, A5, B2, 99, 7F, 37

Answered: The following block of data is stored…

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter2: Problem Solving Using C++using

Section2.5: Variables And Declaration Statements

Problem 11E

See similar textbooks

Similar questions

Given rax = 0x0000000200000100, rbx = 0x0000000000000100, and rcx = 0x0000000000000001,and the following values in memoryaddress -> byte at that address0x0000000000000100 -> 0x010x0000000000000101 -> 0x000x0000000000000102 -> 0x000x0000000000000103 -> 0x000x0000000000000104 -> 0x020x0000000000000105 -> 0x000x0000000000000106 -> 0x000x0000000000000107 -> 0x00what is the new value in %rax after the following operation?subq -0x04(%rbx, %rcx, 4), %rax
A set of eight data bytes is stored in memory locations starting from XX70H. Write a program to add two bytes at a time and store the sum in the same memory locations, low order sum replacing the first byte and a carry replacing the second byte. If any pair does not generate a carry, the memory location of the second byte should be cleared. Data(H) F9, 38, A7, 56,98,52, 8F, F2
Generate MIPS code for the following code segments assuming that all variables are in memory locations.
Translate the following LEGv8 code to C. Assume that the variables f, g, h, i, and j are assigned to registers X0, X1, X2, X3, and X4, respectively. Assume that the base address of the arrays A and B are in registers X6 and X7, respectively. ADDI X9, X6, #8 ADD X10, X6, XZR STUR X10, [X9, #0] LDUR X9, [X9, #0] ADD X0, X9, X10
Convert given code to LEGv8 code:int f, g, y //global 64-bit variablesint sum (int a, int b) { // at memory address X0+1000.return (a +b)} int main (void) // at memory address X0 + 800{f=2;g=3;y= sum (f, g);return y;}Convert this code, making valid assumptions about registers and register use. Notethat brackets and global variable declarations are not affecting the addresses of the instructionsin memory.
Q2/ Write a program to add the followig five data bytes stored in data segment offset starting from [0500H], if the sum generates a carry, stop the adding and store (01) in data segment offset [0600H], otherwise, continue adding and store the sum in data segment offset [0600H],
Show the content of the individual bytes allocated in memory in hexadecimal for the following declarations. Assuming that the address of I is 404000h, what are the addresses of J, K, and L? What is the total number of allocated bytes?
Given the following data definitions, the address of the first variable var1 is given at 0x1001 1000 (hexadecimal). Using little endian, show the memory dump below. Fill each box below with a byte of the allocated memory in hexadecimal. You may use the ASCII table provided. .data var1: .byte 3, -2, ‘A’ var2: .half 1, 256, 0xFFFF var3: .word 0x3DE1C74, 0xFF .align 3 str1: .asciiz "CPS2390" DATA SEGMENT: ADDRESS
In the following code, the first printf() reached produces the output “14,” but the second printf() can cause a bus error or a segmentation fault. Why? main(){ int *p;funct(p);printf("%d\n",*p);}funct(int *p2){p2=(int *)malloc(4);*p2=14;printf("%d\n",*p2);}
Convert below expression into three address code a := (c+d) * (c+b)
Assemble the following two instructions. The first two bytes in binary - indicating its different parts- and the rest in hexadecimal. .DATA vector db 250 dup (?) var dw 4 .CODE ADD var+4[bx-2][si+8],6 MOV dl, vector[bx]
Write a sequence of instructions that shift three memory bytes to the right by 1 bit position.Use the following test data:byteArray BYTE 81h,20h,33h

SEE MORE QUESTIONS

Recommended textbooks for you

C++ for Engineers and Scientists

Computer Science

ISBN:

9781133187844

Author:

Bronson, Gary J.

Publisher:

Course Technology Ptr

C++ for Engineers and Scientists

Computer Science

ISBN:

9781133187844

Author:

Bronson, Gary J.

Publisher:

Course Technology Ptr

SEE MORE TEXTBOOKS

The following block of data is stored in the memory locations from XX55H to XXSAH. Transfer the data to the locations XX80H to XX85H in the reverse order (e.g., the data byte 22H should be stored at XX85H and 37H at XX80H). Data(H) 22, A5, B2, 99, 7F, 37