The following chemical equation represents the reaction that occurs when methylamine dissolves in water to form a basic solution. CH3NH2(aq) + H2O(l) -> CH3NH3+(aq) + OH-(aq) b.) The pH of 2.65 M CH3NH2(aq) is 12.54. Determine the value of Kb for methylamine. A 25.00 mL sample of a CH3NH2(aq) solution of unknown concentration is titrated with 1.84 M HCl(aq). Following is a graph that shows pH versus the volume of 1.84 M HCl(aq) added during the titration.  c.) If 28.25 mL of 1.84 M HCl(aq) was required to reach the equivalence point, calculate the concentration of the CH3NH2(aq) solution of unknown concentration. d.) Using the symbols in the legend above, draw particles in the following beaker to represent the relative amounts of the two pieces, CH3NH2 and CH3NH3+, in the solution after the first 5.00 mL of titrant had been added to the CH3NH2(aq) solution. Beaker after 5.00 mL of 1.84 M HCl(aq) Added e.) Explain why the titration curve shows only a small change in pH per volume of acid added when the total amount of acid is about 14.0 mL. Include a balanced chemical equation as part of your answer.

Chemistry: The Molecular Science
5th Edition
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Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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The following chemical equation represents the reaction that occurs when methylamine dissolves in water to form a basic solution.

CH3NH2(aq) + H2O(l) -> CH3NH3+(aq) + OH-(aq)

b.) The pH of 2.65 M CH3NH2(aq) is 12.54. Determine the value of Kb for methylamine.

A 25.00 mL sample of a CH3NH2(aq) solution of unknown concentration is titrated with 1.84 M HCl(aq). Following is a graph that shows pH versus the volume of 1.84 M HCl(aq) added during the titration. 

c.) If 28.25 mL of 1.84 M HCl(aq) was required to reach the equivalence point, calculate the concentration of the CH3NH2(aq) solution of unknown concentration.

d.) Using the symbols in the legend above, draw particles in the following beaker to represent the relative amounts of the two pieces, CH3NH2 and CH3NH3+, in the solution after the first 5.00 mL of titrant had been added to the CH3NH2(aq) solution.

Beaker after 5.00 mL of 1.84 M HCl(aq) Added

e.) Explain why the titration curve shows only a small change in pH per volume of acid added when the total amount of acid is about 14.0 mL. Include a balanced chemical equation as part of your answer.

 

I know this is a lot, and I'm sorry, but can you please answer them all. Thank you so much! I really appreciate it!

6 of 7
A 25.00 mL sample of a CH3NH, (aq) solution of unknown concentration is titrated with 1.84 M HCI(aq). Following is a graph that shows pH versus the volume of 1.84 M HC1(ag) added
during the titration.
14
13
12
11
10
9+
8
Sub
6-
5+
4+
3+
2-
0-
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32
Volume of 1.84 M HCI(aq) Added (mL)
(c) If 28.25 mL of 1.84 M HClaq) was required to reach the equivalence point, calculate the concentration of the CH3NH, (aq) solution of unknown concentration.
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Transcribed Image Text:6 of 7 A 25.00 mL sample of a CH3NH, (aq) solution of unknown concentration is titrated with 1.84 M HCI(aq). Following is a graph that shows pH versus the volume of 1.84 M HC1(ag) added during the titration. 14 13 12 11 10 9+ 8 Sub 6- 5+ 4+ 3+ 2- 0- 0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Volume of 1.84 M HCI(aq) Added (mL) (c) If 28.25 mL of 1.84 M HClaq) was required to reach the equivalence point, calculate the concentration of the CH3NH, (aq) solution of unknown concentration. EXTD acer ぐ @ 23
CH3NH2
O CH3NH3
(d) Using the symbols in the legend above, draw particles in the following beaker to represent the relative amounts of the two species, CH3NH, and CH3NH,, in the solution after the
5.00 mL of titrant had been added to the CH3NH2 (aq) solution.
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Transcribed Image Text:CH3NH2 O CH3NH3 (d) Using the symbols in the legend above, draw particles in the following beaker to represent the relative amounts of the two species, CH3NH, and CH3NH,, in the solution after the 5.00 mL of titrant had been added to the CH3NH2 (aq) solution. B IU X X2 5 C 0/10000 W 国 acer !!!
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