The following database has 5 transactions. Let min_sup = 60% and min_conf = 80%. TID Items_bought T100 {m, o, n, k, e, y} T200 {d, o, n, k, e, y} T300 {m, a, k, e} T400 {m, u, c, k, y} T500 {c, o, k, i, e} (2) Select all the strong association rules in the format of {item 1, item 2} -> {item 3}. ☐ {k, o} -> {e} ☐ {k, e} -> {o} ☐ {k, e} -> {y} ☐ {e, o} -> {k} ☐ {k, y} -> {e} ☐ {e, y} -> {k}
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- Suppose you are a manufacturer of product ABC, which is composed of parts A, B, and C When a new product is created, the involved parts in table PART must be reduced. As such, when product ABC is created, PROD_QTY is increased by one, and the quantity of parts A, B, and C in table PART (i.e. PART_QTY) is reduced by one respectively. The database content is shown in the following tables. How many database requests can you identify when a product ABC is created? List all.You are given the following database schema:Sailors(sid, sname, rating, age)Boats(bid, bname, color)Reserves(sid, bid, day)Consider the join on Sailors ▷◁ Reserves and assume that you have the following statistics andlimitations: * You have available 9 pages in main memory.* Sailors: 100000 tuples, 1000 pages; Boats: 2000 tuples, 10 pages; Reserves: 110000 tuples,550 pages 1. Calculate the I/O cost of this join using the Block Nested Loop algorithm?You are given the following database schema:Sailors(sid, sname, rating, age)Boats(bid, bname, color)Reserves(sid, bid, day)Consider the join on Sailors ▷◁ Reserves and assume that you have the following statistics andlimitations: * You have available 9 pages in main memory.* Sailors: 100000 tuples, 1000 pages; Boats: 2000 tuples, 10 pages; Reserves: 110000 tuples,550 pages 1. Calculate the I/O cost of this join using the Block Nested Loop algorithm? 2. Calculate the I/O cost of sorting the Sailors relation?
- In the original sample solution, a customer could only have one address. Review the finalized sample solution for the database design. How many addresses can be linked to a customer? a.) Unlimited b.) 1 c.) 2 d.) 4Start a database transaction. Next time we meet, we'll be optimistic.Indexing Consider a relational database that consists of the relational tables created by the following CREATE TABLE statements: CREATE TABLE PART( P_PARTKEY NUMBER(12) NOT NULL, P_NAME VARCHAR(55) NOT NULL, P_RETAILPRICE NUMBER(12,2) NOT NULL, CONSTRAINT PART_PEKEY PRIMARY KEY (P_PARTKEY) ); CREATE TABLE SUPPLIER( S_SUPPKEY NUMBER(12) NOT NULL, S_NAME CHAR(25) NOT NULL S_NATIONKEY NUMBER(12) NOT NULL, S_PHONE CHAR(15) NOT NULL, CONSTRAINT SUPPLIER_PKEY PRIMARY KEY (S_SUPPKEY) ); CREATE TABLE PARTSUPP( PS_PARTKEY NUMBER(12) NOT NULL, PS_SUPPKEY NUMBER(12) NOT NULL, PS_SUPPLYCOST NUMBER(12,2) NOT NULL, CONSTRAINT PARTSUPP_PKEY PRIMARY KEY (PS_PARTKEY, PS_SUPPKEY), CONSTRAINT PARTSUPP_FKEY1 FOREIGN KEY (PS_PARTKEY) REFERENCES PART(P_PARTKEY), CONSTRAINT PARTSUPP_FKEY2 FOREIGN KEY (PS_SUPPKEY) REFERENCES SUPPLIER(S_SUPPKEY) ); Determine what index should be created to improve the performance of the queries listed below in the best possible way. Consider each one of the…
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- From the database scheme write the query(all tables are empty) 1) Insert your name and your phone as a new tenant 2) Delete your phone number from the table tenant. 3) Create a new contract lease for you. 4) Delete the contract that you created. 5) List the city name, city population and country name. 6) List the cities that have the letters “re” in any part of the name; 7) List the tenant name contract number, rent price, when the contract rent price is bigger equal 500 and lower equal 1000. 8) List all columns from apartments with the services offered (all columns from service). 9) List the building address, the city name and the country name for the building in Canada. 10) List the name of the user with the city name and country name, ordering by name of user.It's possible that the referential integrity of a database may be compromised, which would have disastrous effects. What are some of the most frequent errors that you find yourself making?ormulate the following queries in Structured Query Language SQL The following tables form part of a database held in an RDBMS: Employee (empNo, fName, lName, address, DOB, sex, position, salary, deptNo) Department (deptNo, deptName, mgrEmpNo) Project (projNo, projName, deptNo) WorksOn (empNo, projNo, dateWorked, hoursWorked) where Employee contains employee details and empNo is the key. Department contains department details and deptNo is the key. mgrEmpNo identifies the employee who is the manager of the department. There is only one manager foreach department. Project contains details of the projects in each department and the key is projNo (notwo departments can run the same project). WorksOn contains details of the hours worked by employees on each project, and empNo/ projNo/dateWorked form the key. Formulate the following queries in Structured Query Language SQL List all the details of employees who are female and born after 1990. List employee numbers and names of all…
