The following figure shows six pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M-2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Using the letters ABCDEF, rank each pair according to the gravitational force attracting the asteroids to each other, from strongest to weakest. 1) d=1 d=1 M=2 M=1 M=2 M=2 2) 5) d=2 d=2 M=1 M=2 M=2 M=2 3) d=2 d=3 M=1 M=1 М-2 M=2 A) Pair 5 B) Pair 3 C) Pair 1 D) Pair 6 E) Pair 2

Principles of Physics: A Calculus-Based Text
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Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
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The following figure shows six pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Using the letters ABCDEF, rank
each pair according to the gravitational force attracting the asteroids to each other, from strongest to weakest.
1)
4)
d=1
d=1
M=2
M=1
M=2
M=2
2)
5)
d=2
d=2
M=1
M=2
M=2
M=2
3)
d=2
d=3
M=1
M=1
M=2
M=2
A) Pair 5
B) Pair 3
C) Pair 1
D) Pair 6
E) Pair 2
Transcribed Image Text:The following figure shows six pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Using the letters ABCDEF, rank each pair according to the gravitational force attracting the asteroids to each other, from strongest to weakest. 1) 4) d=1 d=1 M=2 M=1 M=2 M=2 2) 5) d=2 d=2 M=1 M=2 M=2 M=2 3) d=2 d=3 M=1 M=1 M=2 M=2 A) Pair 5 B) Pair 3 C) Pair 1 D) Pair 6 E) Pair 2
Expert Solution
Step 1

Gravitational force of attraction is given be:

F = Gm1m2r2

Now we calculate force for all 6 pairs:

1) F = G x2 x112 = 2G

2) F = G x 2 x 222= G

3)  F= G x 1 x122 = G4

4)F= G x 2 x212 = 4G

5) F = G x 2 x122 = G2

6) F = G x 2 x232 = 4 G9

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