The following program has a function getlnt() that gets input from the input box and converts it to an integer, and a main() function that calls getInt() twice to get two integers, then divides the first integer (dividend) by the second (divisor) and prints the result. Add exception code to getlnt() so when the input cannot be converted to an integer (e.g., it's a letter, word, or floating point number), it ignores it and gets the next input, and keeps doing that until it gets an integer. Add exception code to main() so when the divisor (second integer) is zero, it prints "Cannot divide by zero." and ends. For example, when the input is: 4 the output is: 2.0 When the input is: four 4 zero

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter14: Exception Handling
Section: Chapter Questions
Problem 22SA
icon
Related questions
Question
LAB
12.4.1: Exception handlers in functions
0/10
АCTIVITY
main.py
Load default template...
1 def getInt():
again = True
while again:
# add exception code here
integer
again
# add exception-handler here
continue
4
5
int(input())
False
7
8.
9.
return integer
10 def main(():
getInt() # get dividend
# get divisor
11
dividend
divisor = getInt()
# add exception code here
12
13
14
answer =
dividend/divisor
print("Answer:", answer)
# add exception-handler here
print("Cannot divide by zero.")
15
16
17
18 main()
Transcribed Image Text:LAB 12.4.1: Exception handlers in functions 0/10 АCTIVITY main.py Load default template... 1 def getInt(): again = True while again: # add exception code here integer again # add exception-handler here continue 4 5 int(input()) False 7 8. 9. return integer 10 def main((): getInt() # get dividend # get divisor 11 dividend divisor = getInt() # add exception code here 12 13 14 answer = dividend/divisor print("Answer:", answer) # add exception-handler here print("Cannot divide by zero.") 15 16 17 18 main()
12.4 Exception handlers in functions
The following program has a function getlnt() that gets input from the input box and converts it to an integer, and a main() function that
calls getlnt() twice to get two integers, then divides the first integer (dividend) by the second (divisor) and prints the result.
Add exception code to getlnt() so when the input cannot be converted to an integer (e.g., it's a letter, word, or floating point number), it
ignores it and gets the next input, and keeps doing that until it gets an integer.
Add exception code to main() so when the divisor (second integer) is zero, it prints "Cannot divide by zero." and ends.
For example, when the input is:
4
the output is:
2.0
When the input is:
four
4
zero
the output is:
Cannot divide by zero.
288520.1835062.qx3zqy7
Transcribed Image Text:12.4 Exception handlers in functions The following program has a function getlnt() that gets input from the input box and converts it to an integer, and a main() function that calls getlnt() twice to get two integers, then divides the first integer (dividend) by the second (divisor) and prints the result. Add exception code to getlnt() so when the input cannot be converted to an integer (e.g., it's a letter, word, or floating point number), it ignores it and gets the next input, and keeps doing that until it gets an integer. Add exception code to main() so when the divisor (second integer) is zero, it prints "Cannot divide by zero." and ends. For example, when the input is: 4 the output is: 2.0 When the input is: four 4 zero the output is: Cannot divide by zero. 288520.1835062.qx3zqy7
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Exception Handling Keywords
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
C++ Programming: From Problem Analysis to Program…
C++ Programming: From Problem Analysis to Program…
Computer Science
ISBN:
9781337102087
Author:
D. S. Malik
Publisher:
Cengage Learning