Please don't provide handwritten solution ... The following results were found after completion of Part C in the Experimental procedure:0.049 MI and 0.069 M H₂O2 were usedRun Catalyst12Calculated Rate ofReaction (M/s)0.47none10.00mLof 0.28 M 2.49FeCl2Assuming the Rate Law = k[1]2[H₂O₂] ²2Calculate the value of k for run 2. Give your answer to the nearest whole number.

Adding a catalyst increases the rate of reaction by providing a path with lower activation energy…

The following results were found after completion of Part C in the Experimental procedure: 0.049 MI and 0.069 M H₂O2 were used Calculated Rate of Reaction (M/s) 0.47 Run Catalyst 1 2 none 10.00mL of 0.28 M 2.49 |FeCl2 Assuming the Rate Law = K[1]²[H₂O₂]² Calculate the value of k for run 2. Give your answer to the nearest whole number.

The following results were found after completion of Part C in the Experimental procedure: 0.049 MI and 0.069 M H₂O2 were used Calculated Rate of Reaction (M/s) 0.47 Run Catalyst 1 2 none 10.00mL of 0.28 M 2.49 |FeCl2 Assuming the Rate Law = K[1]²[H₂O₂]² Calculate the value of k for run 2. Give your answer to the nearest whole number.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter30: Kinetic Methods Of Analysis

Section: Chapter Questions

Problem 30.9QAP

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