The force acting on the gear tooth is F=40 KN. Resolve this force into two components acting along the lines aa and bb F. a 60° 40° a F_a=30.17 KN, F_b3D21.10 KN F_a=35.17 KN, F_b=26.10 KN F_a=25.17 KN, F_63D22.10 KN F_a=15.17 KN, F_b=15.10 KN

International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.75P: The single-plate clutch transmits the torque C from the input shaft on the left to the output shaft...
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The force acting on the gear tooth is
F=40 KN. Resolve this force into two
components acting along the lines aa and
bb *
b
F
60°
40°
b'
F_a=30.17 KN, F_b=D21.10 KN
F_a=35.17 KN, F_b=26.10 KN
O F_a=25.17 KN, F_b=22.10 KN
F_a=15.17 KN, F_b=15.10 KN
口
Transcribed Image Text:12:01 PM A O 1 26 A docs.google.com/forms/ M 16 This is a required question The force acting on the gear tooth is F=40 KN. Resolve this force into two components acting along the lines aa and bb * b F 60° 40° b' F_a=30.17 KN, F_b=D21.10 KN F_a=35.17 KN, F_b=26.10 KN O F_a=25.17 KN, F_b=22.10 KN F_a=15.17 KN, F_b=15.10 KN 口
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